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Jack Benning
Jack Benning

Reputation: 501

How to count the number of occurences of urls and hyperlinks in a Ruby string?

Say a user submits this comment on a blog:

@SO - Great community, but we've also seen some great communities at Stack Overflow. At the same time Google's Gmail (http://gmail.com) is a great example of a community with endless bounds. I'm just wondering if anyone will really go toe-to-toe with something like http://www.twitter.com. What do you think?

Note: the 3rd url was actually posted as plain text, but SO converted it to a hyperlink.

Anyways, the total url and hyperlink count should be 3.

So, from a Ruby and/or Ruby on Rails perspective: How to count the number of occurences of urls and hyperlinks in a Ruby string?

Upvotes: 2

Views: 244

Answers (3)

Toby Hede
Toby Hede

Reputation: 37133

This is pretty easy, albeit relatively naive:

string.count("http://")

Of course, it won't pick up links without a leading "http://", but that might be a reasonable assumption.

Upvotes: 1

Pablo Santa Cruz
Pablo Santa Cruz

Reputation: 181350

Using regular expressions is a good way. Here is an example on how to do that:

yourpost.each do |yourword|
     if yourword =~ /^(((ht|f)tps?\:\/\/)|~/|/)?([a-zA-Z]{1}([\w\-]+\.)+([\w]{2,5})(:[\d]{1,5})?)/?(\w+\.[\w]{3,4})?((\?\w+=\w+)?(&\w+=\w+)*)?/
            puts %Q!We found #{$&} an URL in #{$1}!
    end
end

See this post for further discussion on regular expressions matching URLs.

Upvotes: 0

fl00r
fl00r

Reputation: 83680

The easiest way is to scan for "http" pattern, but really it can be more complicated, because sometimes urls haven't got "http://" at the beggining

string = "@SO - Great community, but we've also seen some great communities at <a href='http://blabla'>Stack Overflow</a>. At the same time Google's Gmail (http://gmail.com) is a great example of a community with endless bounds. I'm just wondering if anyone will really go toe-to-toe with something like http://www.twitter.com. What do you think?"
string.scan(/http/).size #=> 3

Upvotes: 0

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