Reputation: 3465
Currently, I've just defined simple rules in ANTLR4:
// Recognizer Rules
program : (class_dcl)+ EOF;
class_dcl: 'class' ID ('extends' ID)? '{' class_body '}';
class_body: (const_dcl|var_dcl|method_dcl)*;
const_dcl: ('static')? 'final' PRIMITIVE_TYPE ID '=' expr ';';
var_dcl: ('static')? id_list ':' type ';';
method_dcl: PRIMITIVE_TYPE ('static')? ID '(' para_list ')' block_stm;
para_list: (para_dcl (';' para_dcl)*)?;
para_dcl: id_list ':' PRIMITIVE_TYPE;
block_stm: '{' '}';
expr: <assoc=right> expr '=' expr | expr1;
expr1: term ('<' | '>' | '<=' | '>=' | '==' | '!=') term | term;
term: ('+'|'-') term | term ('*'|'/') term | term ('+'|'-') term | fact;
fact: INTLIT | FLOATLIT | BOOLLIT | ID | '(' expr ')';
type: PRIMITIVE_TYPE ('[' INTLIT ']')?;
id_list: ID (',' ID)*;
// Lexer Rules
KEYWORD: PRIMITIVE_TYPE | BOOLLIT | 'class' | 'extends' | 'if' | 'then' | 'else'
| 'null' | 'break' | 'continue' | 'while' | 'return' | 'self' | 'final'
| 'static' | 'new' | 'do';
SEPARATOR: '[' | ']' | '{' | '}' | '(' | ')' | ';' | ':' | '.' | ',';
OPERATOR: '^' | 'new' | '=' | UNA_OPERATOR | BIN_OPERATOR;
UNA_OPERATOR: '!';
BIN_OPERATOR: '+' | '-' | '*' | '\\' | '/' | '%' | '>' | '>=' | '<' | '<='
| '==' | '<>' | '&&' | '||' | ':=';
PRIMITIVE_TYPE: 'integer' | 'float' | 'bool' | 'string' | 'void';
BOOLLIT: 'true' | 'false';
FLOATLIT: [0-9]+ ((('.'[0-9]* (('E'|'e')('+'|'-')?[0-9]+)? ))|(('E'|'e')('+'|'-')? [0-9]+));
INTLIT: [0-9]+;
STRINGLIT: '"' ('\\'[bfrnt\\"]|~[\r\t\n\\"])* '"';
ILLEGAL_ESC: '"' (('\\'[bfrnt\\"]|~[\n\\"]))* ('\\'(~[bfrnt\\"]))
{if (true) throw new bkool.parser.IllegalEscape(getText());};
UNCLOSED_STRING: '"'('\\'[bfrnt\\"]|~[\r\t\n\\"])*
{if (true) throw new bkool.parser.UncloseString(getText());};
COMMENT: (BLOCK_COMMENT|LINE_COMMENT) -> skip;
BLOCK_COMMENT: '(''*'(('*')?(~')'))*'*'')';
LINE_COMMENT: '#' (~[\n])* ('\n'|EOF);
ID: [a-zA-z_]+ [a-zA-z_0-9]* ;
WS: [ \t\r\n]+ -> skip ;
ERROR_TOKEN: . {if (true) throw new bkool.parser.ErrorToken(getText());};
I opened the parse tree, and tried to test:
class abc
{
final integer x=1;
}
It returned errors:
BKOOL::program:3:8: mismatched input 'integer' expecting PRIMITIVE_TYPE
BKOOL::program:3:17: mismatched input '=' expecting {':', ','}
I still haven't got why. Could you please help me why it didn't recognize rules and tokens as I expected?
Upvotes: 1
Views: 3704
Reputation: 51330
Lexer rules are exclusive. The longest wins, and the tiebreaker is the grammar order.
In your case; integer
is a KEYWORD
instead of PRIMITIVE_TYPE
.
What you should do here:
KEYWORD
rule.PRIMITIVE_TYPE
into a parser ruleRight now, your example:
class abc
{
final integer x=1;
}
Gets converted to lexemes such as:
class
ID
{
final
KEYWORD
ID
=
INTLIT
;
}
This is thanks to the implicit token typing, as you've used definitions such as 'class'
in your parser rules. These get converted to anonymous tokens such as T_001 : 'class';
which get the highest priority.
If this weren't the case, you'd end up with:
KEYWORD
ID
SEPARATOR
KEYWORD
KEYWORD
ID
OPERATOR
INTLIT
;
SEPARATOR
And that's... not quite easy to parse ;-)
That's why I'm telling you to breakdown your tokens properly.
Upvotes: 4