Reputation: 5836
I have a input-file
for a code, which has a parameter called var1
. I need to run a bash script to read and change var1
inside the input-file
and submit to the code.
Inside the input-file
:
...
var1=10
...
I can use grep
to get value of var1
. But how to replace and write var1
inside the input-file
?
Command I use to obtain var1
INPUT=input-file
var1=`grep "^var1" $INPUT | awk '{print $3}' | sed "s/'//g"`
Upvotes: 0
Views: 3266
Reputation: 75
This worked for me:
sed -i -e 's/\(^var1=\).*/\1Newvalue/' $INPUT
Upvotes: 0
Reputation: 195059
grep doesn't do any substitution. You could consider using sed or awk ... For example:
sed -i 's/\(^var1=\).*/\1Newvalue/' $INPUT
will change the value to Newvalue
Upvotes: 3