Reputation: 5459
I am trying to create a simple application which involves a jsp page (which is just a textarea to enter a query and a submit button) a Query class (very simple class shown below) and a QueryController to interact with the two. I am trying to have the QueryController print to console to test it but no output is being printed to Standard.out
. Clicking the submit button takes me to http://localhost:8080/<PROJECT_NAME>/?queryField=<QUERY_TEXT>
which results in a 404 error since it is not a valid webpage. The three [simple] classes are shown below. Help is appreciated.
Query class:
public class Query {
private String query;
public String getQuery() {
return query;
}
public void setQuery(String query) {
this.query = query;
}
}
query.jsp:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<body>
<form action="query" method="post" commandName="queryForm">
<textarea name="queryField" cols="55" rows="1"></textarea><br>
<input type="submit" value="submit">
</form>
</body>
</html>
and my simple QueryController.java:
@Controller
@RequestMapping(value = "/query")
public class QueryController {
@RequestMapping(method = RequestMethod.POST)
public String processRegistration(@ModelAttribute("queryForm") Query query,
Map<String, Object> model) {
// for testing purpose:
System.out.println("query (from controller): " + query.getQuery());
return "someNextPageHere";
}
}
Upvotes: 0
Views: 9934
Reputation: 10565
We would need more configuration to Spring
modules to get this working. You may go with Option 1 - with web.xml
or Option 2 - without web.xml
:
1. Modify your web.xml
to:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>SimpleProject</display-name>
<servlet>
<servlet-name>SimpleProjectServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/config/SimpleProjectServlet-servlet.xml
</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>SimpleProjectServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>query.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
2. Create file with path - WEB-INF/config/SimpleProjectServlet-servlet.xml
3. Add following contents to the file created in Step 2. You would need to edit the Spring version references:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.2.xsd">
<context:component-scan base-package="com.mycompany.myproject" />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/views/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<mvc:resources mapping="/resources/**" location="/resources/" />
<mvc:annotation-driven />
</beans>
4. Set right package name as you have in the above configuration at context:component-scan
1. Delete your web.xml
2. Add Java Config
for annotation based Spring MVC
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter;
import org.springframework.web.servlet.view.InternalResourceViewResolver;
import org.springframework.web.servlet.view.JstlView;
@EnableWebMvc
@Configuration
@ComponentScan({ "com.mycompany.myproject" })
public class SpringWebConfig extends WebMvcConfigurerAdapter {
@Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/resources/**").addResourceLocations(
"/resources/");
}
@Bean
public InternalResourceViewResolver viewResolver() {
InternalResourceViewResolver viewResolver = new InternalResourceViewResolver();
viewResolver.setViewClass(JstlView.class);
viewResolver.setPrefix("/WEB-INF/views/jsp/");
viewResolver.setSuffix(".jsp");
return viewResolver;
}
}
3. Modify SpringWebConfig
with the right package at @ComponentScan
4. Add Java Config
for WebApplication
. Create a class extending WebApplicationInitializer
with required configurations:
import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.ServletRegistration;
import org.springframework.web.WebApplicationInitializer;
import org.springframework.web.context.support.AnnotationConfigWebApplicationContext;
import org.springframework.web.servlet.DispatcherServlet;
public class MyWebAppInitializer implements WebApplicationInitializer {
public void onStartup(ServletContext container) throws ServletException {
AnnotationConfigWebApplicationContext ctx = new AnnotationConfigWebApplicationContext();
ctx.register(SpringWebConfig.class);
ctx.setServletContext(container);
ServletRegistration.Dynamic servlet = container.addServlet(
"dispatcher", new DispatcherServlet(ctx));
servlet.setLoadOnStartup(1);
servlet.addMapping("/");
}
}
Here we had few configuration part that was resulting in this error:
DispatcherServlet
was configured to accept url with views/*
src\main\java
to WEB-INF\classes
Spring 3
running on Tomcat 8
which defaults to JDK-8
and ASM Loader
could not load files. Had to move to Spring version 4.0.1-RELEASE
Upvotes: 3
Reputation: 21
You query.jsp file need some change. From:
<textarea name="queryField" cols="55" rows="1"></textarea>
To:
<textarea name="queryField" path="query" cols="55" rows="1"></textarea>
You need to specify path attribute in order to use Spring form handling. Need of path attribute: it maps the form element (text area in this case) to a variable of POJO class (private String query of Query class).
Upvotes: 2
Reputation: 1599
I think you need to add a config file and in your web.xml you should add the declaration for it like: web.xml
...
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
...
in your appServlet-servlet.xml, you should declare the annotation scan like:
<tx:annotation-driven />
<mvc:annotation-driven />
<context:annotation-config />
<context:component-scan base-package="abc.xyz"/>
Hope this help!
Upvotes: 0