CODEWITHSUNDEEP
pythonlist
louiestacked
louiestacked

Reputation: 41

Print nested list in a format of "XX to XX"

I'm new to python so I have been trying to figure out how to print the following list in the format below. I have tried to get them through indexes but it doesn't seem to work out.

So I have a list of tuples that I need to print out in the following format:

1. A1 to B1
2. C1 to D2 , C1 to B2

This is the following list I have that I need to convert to that format.

[['A1', 'B1'], ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'A3', 'C1', 'F4', 'C1', 'G5', 'C1', 'H6'], ['E1', 'D1', 'E1', 'F2', 'E1', 'D2', 'E1', 'G3', 'E1', 'H4']]

Upvotes: 1

Views: 138

Answers (5)

Irshad Bhat
Irshad Bhat

Reputation: 8709

Here is one way of doing this:

>>> l = [['A1', 'B1'], ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'A3', 'C1', 'F4', 'C1', 'G5', 'C1', 'H6'], ['E1', 'D1', 'E1', 'F2', 'E1', 'D2', 'E1', 'G3', 'E1', 'H4']]
>>>
>>>
>>> for i,m in enumerate(l):
...    print '%s. %s' %(i+1, ' , '.join([' to '.join(n) for n in zip(m[::2], m[1::2])]))
... 
1. A1 to B1
2. C1 to D2 , C1 to B2 , C1 to E3 , C1 to A3 , C1 to F4 , C1 to G5 , C1 to H6
3. E1 to D1 , E1 to F2 , E1 to D2 , E1 to G3 , E1 to H4

Upvotes: 0

Ozgur Vatansever
Ozgur Vatansever

Reputation: 52133

>>> tuples = [['A1', 'B1'], 
...           ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'C2'], 
...           ['E1', 'D1', 'E1', 'F2']]

>>> for i, sequence in enumerate(tuples, 1):
...     it = iter(sequence)
...     print(i, ', '.join('{} to {}'.format(x, y) for x, y in zip(it, it))

1 A1 to B1
2 C1 to D2, C1 to B2, C1 to E3, C1 to C2
3 E1 to D1, E1 to F2

You must replace zip() with itertools.izip_longest() if number of elements in the list is odd:

>>> from itertools import izip_longest

>>> tuples = [['A1', 'B1', 'T1'], 
              ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'C2', 'Z1'],
              ['E1', 'D1', 'E1', 'F2']]

>>> for i, sequence in enumerate(tuples, 1):
...     it = iter(sequence)
...     print(i, ', '.join('{} to {}'.format(x, y) 
...                        for x, y in izip_longest(it, it, fillvalue='X'))

1 A1 to B1, T1 to X
2 C1 to D2, C1 to B2, C1 to E3, C1 to C2, Z1 to X
3 E1 to D1, E1 to F2

Upvotes: 5

TessellatingHeckler
TessellatingHeckler

Reputation: 28983

start_list = [['A1', 'B1'], ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'A3', 
             'C1', 'F4', 'C1', 'G5', 'C1', 'H6'], ['E1', 'D1', 'E1', 'F2', 'E1', 'D2',
             'E1', 'G3', 'E1', 'H4']]

for line, sublist in enumerate(start_list):
    pairs_list = [ (a + " to " + b) for (a, b) in zip(sublist, sublist[1:]) ]
    print str(line)+'.', ', '.join(pairs_list)

OK, enough dense advanced code only answers.

start_list = [['A1', 'B1'], ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'A3', 
             'C1', 'F4', 'C1', 'G5', 'C1', 'H6'], ['E1', 'D1', 'E1', 'F2', 'E1', 'D2',
             'E1', 'G3', 'E1', 'H4']]

#Loop over the inner lists, with a counter
for line_num, sublist in enumerate(start_list):

    # Build up a string to print with a line number and dot
    output = str(line_num) + '. '

    # Count through the list of pairs, step 2
    # skipping every other one
    for i in range(0, len(sublist), 2):
        # take the current and next sublist item, into the output string
        # and add a trailing comma and space, to give the form 
        # "A to B, "
        output += sublist[i] + " to " + sublist[i+1] + ", "

    # remove trailing comma after last pair in the line
    output = output.rstrip(', ')

    print output

e.g.

0. A1 to B1
1. C1 to D2, C1 to B2, C1 to E3, C1 to A3, C1 to F4, C1 to G5, C1 to H6
2. E1 to D1, E1 to F2, E1 to D2, E1 to G3, E1 to H4

Upvotes: 2

The6thSense
The6thSense

Reputation: 8335

Using loop and list comprehension

This would also work for lists with odd elements

Code:

lst=[['A1', 'B1'], ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'A3', 'C1', 'F4', 'C1', 'G5', 'C1', 'H6','H5'], ['E1', 'D1', 'E1', 'F2', 'E1', 'D2', 'E1', 'G3', 'E1', 'H4']]
for count,line in enumerate(lst )  :
    print str(count)+" , ".join([" %s to %s" %(tuple((line[i:i+2]))) if i+1 <len(line) else "Single king %s"%(line[i])  for i in range(0,len(line),2)])

Output:

0 A1 to B1
1 C1 to D2 ,  C1 to B2 ,  C1 to E3 ,  C1 to A3 ,  C1 to F4 ,  C1 to G5 ,  C1 to H6 , Single king H5
2 E1 to D1 ,  E1 to F2 ,  E1 to D2 ,  E1 to G3 ,  E1 to H4

Upvotes: 0

Javier
Javier

Reputation: 2776

The easier way to do this for you will be to iterate over the inner lists using an index and an offset.

Something like this (not tested):

for j, inner in enumerate(list_of_lists):
    print(j, '.', sep='', end=' ')
    for i in range(0, len(inner)-1, 2):
        print(inner[i], 'to', inner[i+1], ',', end='')

Upvotes: 0

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