CODEWITHSUNDEEP
javaarrays
Akshay
Akshay

Reputation: 2785

Adding remaining numbers in an array - Java

So I asked a question earlier here, in which the numbers in an array should be added together till the length of 12.

Now, how would I add the remaining numbers, lets say

double[] addMe = {147.04, 147.66, 148.27, 148.89, 149.51, 150.13, 150.76, 151.39, 152.02, 152.65, 153.29, 153.29, 
                10, 20 ,30,40,50,60,70,80,90,100,110,120, 10,20};

from the above I get an answer of 

1804.9
780.0
1804.9

but it missed the last two numbers 10 and 20, how would I add both of them if the count is not equal to 12?

Thanks.

Upvotes: 1

Views: 168

Answers (4)

Niklas Rosencrantz
Niklas Rosencrantz

Reputation: 26671

class Sum {
    public static void main(String[] arguments) {
        double[] addMe = {
            147.04, 147.66, 148.27, 148.89, 149.51, 150.13, 150.76, 151.39, 152.02, 152.65, 153.29, 153.29,
            10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 10, 20
        };
        double sum = 0.0;
        double remainder = 0.0;

        for (int i = 0; i < addMe.length; i++) {
            if (i >= (addMe.length - addMe.length / 12)) {
                remainder = remainder + addMe[i];
            }
            if (i % 12 == 0 && i != 0) {
                System.out.println(sum);
                sum = 0;
            }

            sum += addMe[i];
        }
        System.out.println("Remainder sum: " + remainder);
    }
}

Upvotes: 1

Archytekt
Archytekt

Reputation: 21

You have to print it out of the loop, since it becomes empty before it can be evenly divided by 12, it doesn't successfully print, that is why you add the print statement outside of the loop, so when it finishes, it will print the remaining sum.

    double[] addMe = {147.04, 147.66, 148.27, 148.89, 149.51, 150.13, 150.76, 151.39, 152.02, 152.65, 153.29, 153.29, 
            10, 20 ,30,40,50,60,70,80,90,100,110,120, 10,20};

    double sum=0.0;
    int y = 0;
    for(int i=0;i<addMe.length;i++)
    {

      if(i%12==0 && i!=0)
      {
          y++;
        System.out.print(y+": "+sum+"\n");
        sum=0;
      }else{
          sum +=addMe[i];
      }

    }
    y++;
    System.out.println(y+": "+sum);

Output

1: 1804.9
2: 770.0
3: 20.0

Upvotes: 1

Bhushan
Bhushan

Reputation: 6181

Try this: (If you require to print sum within loop, else the above answer by @L-X is better solution).

double sum=0.0;
for(int i=0;i<addMe.length;i++)
{
  if(i%12==0 && i!=0)
  {
    System.out.println(sum);
    sum=0;
  }    
  sum +=addMe[i];
  if(i==addMe.length-1)
      System.out.println(sum);
}

Upvotes: 1

Sanjeev
Sanjeev

Reputation: 4375

modify this much, You are adding all the numbers , it just you are not printing the last sum if elements are less than 12

 double sum=0.0;
for(int i=0;i<addMe.length;i++)
{
  if(i%12==0 && i!=0)
  {
    System.out.println(sum);
    sum=0;
  }

  sum +=addMe[i];
}
System.out.println(sum);//Just add this outside the loop

Upvotes: 3

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