Reputation: 3548
I need to put an std::vector
into an std::stack
.
Here is my method so far(I am building a card game) :
void CardStack::initializeCardStack(std::vector<Card> & p_cardVector) {
m_cardStack = std::stack<Card>();
//code that should initialize m_cardStack with p_cardVector
}
Note : I cannot change my method signature because it is a imposed by a teacher...
Do I have to iterate over the whole vector ? What is the most efficient way to do this ? The documentation.
I have tried Jens answer but it didn't work.
Upvotes: 5
Views: 5752
Reputation: 9416
std::stack
doesn't have a constructor which accepts iterators, so you could construct a temporary deque
and initialize the stack with this:
void ClassName::initializeStack(std::vector<AnotherClass> const& v) {
m_stackAttribute = std::stack<AnotherClass>( std::stack<AnotherClass>::container_type(v.begin(), v.end()) );
}
However, this copies each element into the container. For maximum efficiency, you should also use move-semantics to eliminate copies
void ClassName::initializeStack(std::vector<AnotherClass>&& v) {
std::stack<AnotherClass>::container_type tmp( std::make_move_iterator(v.begin()), std::make_move_iterator( v.end() ));
m_stackAttribute = std::stack<AnotherClass>( std::move(tmp) );
}
Upvotes: 4
Reputation: 114539
The most efficient way is not using an std::stack
at all and just use a std::vector
or even better for this use a std::deque
.
I've seen and written a lot of C++ code (a lot) but I've yet to find any use for the stack
stuff (any meaningful use, that is). It would be different if the underlying container could be changed or having its container type determined at runtime, but this is not the case.
To copy the elements from an std::vector
into a std::deque
you can just use
std::deque<T> stack(vec.begin(), vec.end());
This will allow the implementation to use the most efficient way to copy the elements.
To explicitly answer your question: yes, the only way to put elements in a stack is to push them in with a loop. This is not efficient but the stack interface doesn't define anything else. However who wrote code accepting an std::stack
parameter should be fired (unless s/he promises that it will never happen again) and its code reverted to something more sensible: you would get the same (absence of) "flexibility" but a better interface.
The design problem of stack
is that it's parametrized on the underlying container type while instead (to have any meaning) should have been parametrized on the contained element type and receving in the constructor a container for that type (thus hiding the container type). In its present form is basically useless.
Upvotes: 0