CODEWITHSUNDEEP
pythonnumpyrandom
unj2
unj2

Reputation: 53481

How do I create a deterministic Random number generator with numpy seed?

As I understand the syntax is 

In[88]: np.random.seed(seed=0)

In[89]: np.random.rand(5) < 0.8
Out[89]: array([ True,  True,  True,  True,  True], dtype=bool)
In[90]: np.random.rand(5) < 0.8
Out[90]: array([ True,  True, False, False,  True], dtype=bool)

However, when I run the rand(), I get different results. Is there something I am missing with the seed function?

Upvotes: 11

Views: 7320

Answers (1)

Zizouz212
Zizouz212

Reputation: 4998

Think of a generator:

def gen(start):
    while True:
        start += 1
        yield start

That will continuously give the next number from the number you insert to the generator. With seeds, it's nearly the same concept. I try to set a variable in which to generate data from, and the position in within that is still saved. Let's put this into practice:

>>> generator = gen(5)
>>> generator.next()
6
>>> generator.next()
7

If you want to restart, you need to restart the generator as well:

>>> generator = gen(5)
>>> generator.next()
6

The same idea with the numpy object. If you want the same results over time, you need to restart the generator, with the same arguments.

>>> np.random.seed(seed=0)
>>> np.random.rand(5) < 0.8
array([ True,  True,  True,  True,  True], dtype=bool)
>>> np.random.rand(5) < 0.8
array([ True,  True, False, False,  True], dtype=bool)
>>> np.random.seed(seed=0) # reset the generator!
>>> np.random.rand(5) < 0.8
array([ True,  True,  True,  True,  True], dtype=bool)

Upvotes: 12

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