Reputation: 57996
I have simple table that has about 80 rows, which I populate dynamically using PHP. What I am trying to do is to layout those rows in chunks for each column. So if I have 80 rows, I would like 4 columns of 20 rows or so, maybe the last column has less or more depending on the total number of rows. The total number of rows can change!
I am having trouble coming up with an implementation method that will not get messy! Anyone know of a simple way that I can implement this.
I have tried using a counter as I loop the data to populate the table and when a multiple of of 20 is reached move to the next block but that didn't work for me as I had extra rows left over.
foreach($indexes as $index){
$counter++;
echo '<tr>';
if($counter > 20){
$multiplier = $counter / 20;
$head = '<td></td>';
for($i=1; $i<$multiplier; $i++){
$head .= '<td></td>';
}
}
if($counter < 20){
$head = '';
}
echo "$head<td>$index</td><td><input id='$index' name='$index' type='checkbox' /></td>";
echo '</tr>';
}
Thanks all for any help
Upvotes: 0
Views: 881
Reputation: 91518
I would do :
$nbCols = 4;
$nbRows = count($indexes)/$nbCols;
for($row=0; $row<$nbRows; $row++) {
echo "<tr>";
for($i=0; $i<$nbCols; $i++) {
$index = $indexes[$row + ($i*$nbRows)];
echo "<td>$index</td><td><input id='$index' name='$index' type='checkbox' /></td>";
}
echo "</tr>";
}
Upvotes: 1
Reputation: 4926
if you dont mind to have this kind of cell order:
1 2 3 4
5 6 7 8
you can use <div style='float:left'>$cellValue</div>
in the loop without use of table.
Upvotes: 0
Reputation: 11855
Wouldn't you want to see the remainder of your division and deal with that also?
if($counter % 20 == 0){
// You've no remainder
}else{
// Do another loop to output the odd rows
}
Or you could % 2 == 0
to see if it's even, and then just multiply the whole result by 10.
Be sure to look at ceil()
and floor()
also for ensuring your number of rows is a round number.
Upvotes: 0