Reputation: 1000
I need your help again. This should be a function for php. I've got two dates. One is set by myDate and the other one is the date of today. I want to find out the number of days left to myDate, but saturday and sundy should be excluded. The result for this function would be 7... How can I make it work?
<?php
myDate = "29.07.2010 "
DaysTillmyDate = 0
iterate day to myDate {
if (date/day is a weekday(Monday,Tuesday,Wednesday,Thursday, Friday))
increment DaysTillmyDate by 1
}
?>
A hint or any help would be much appreciated. Faili
Upvotes: 1
Views: 787
Reputation: 2547
Quick iteration:
$days = 0;
for($i = time(); $i < (strtotime('29.07.2010') + 86400); $i=$i+86400)
{
$weekday = date('w', $i);
if($weekday > 0 && $weekday < 6)
{
$days++;
}
}
echo $days;
Upvotes: 3
Reputation: 24577
date('N', $theDate)
gives you the day of the week (6 for Saturday and 7 for Sunday). From there, you can easily implement a function that does only counts workdays. On the other hand, this does not detect holidays.
Upvotes: 0