CODEWITHSUNDEEP
pythongroovyvirtualenv
Anthony
Anthony

Reputation: 35938

How to execute shell command with && in groovy

I would like to execute the following shell command

workon foo && python /path/to/bar.py --parm1 /path/p1 --parm2 /path/p2

I've tried running it like this 

    def sout = new StringBuffer(), serr = new StringBuffer()
    def proc = ["/bin/zsh","-c"," workon foo", "&&", "python", "/path/to/bar.py", "--parm1", "/path/p1", "--parm2", "/path/p2"].execute()
    proc.consumeProcessOutput(sout, serr)
    proc.waitForOrKill(1000)
    println "out> $sout err> $serr"

but I keep getting errors:

out>  err> zsh:1: command not found: workon

I can execute this command from the terminal

Upvotes: 0

Views: 766

Answers (1)

DBagBaggerWithSwagger
DBagBaggerWithSwagger

Reputation: 158

As @donkopotamus suggested it's likely that workon is not in your path nor setup (via environment initialization) when zsh -c is called. It's likely that you need a "login shell" to do this -but note that I don't use or know much about zsh :)

Try running zsh -l -c COMMAND.

In addition, the way you're calling zsh with -c, it can only process one command. Everything else will be treated as arguments to that command.

To use &&, you'll have to assign this to proc:

["/bin/zsh","-lc", "workon foo && python /path/to/bar.py ..."]

Notice that the argument to -c is one string.

Upvotes: 2

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