CODEWITHSUNDEEP
ctokenizestrtok
Jack
Jack

Reputation: 722

get the last token of a string in C

what I want to do is given an input string, which I will not know it's size or the number of tokens, be able to print it's last token.

e.x.: 

char* s = "some/very/big/string";
char* token;

const char delimiter[2] = "/";

token = strtok(s, delimiter);

while (token != NULL) {
    printf("%s\n", token);
    token = strtok(NULL, delimiter);
}

return token;

and i want my return to be

string

but I what I get is (null). Any workarounds? I've searched the web and can't seem to find an answer to this. At least for C programming language.

Upvotes: 5

Views: 20661

Answers (2)

Sergey Kalinichenko
Sergey Kalinichenko

Reputation: 726579

If you tokenize on a specific character, i.e. '/' in your example, you do not need to tokenize the string at all: call strrchr to find the position of the last '/', and add 1 to the resultant pointer to skip the delimiter, like this:

char *s = "some/very/big/string";
char *last = strrchr(s, '/');
if (last != NULL) {
    printf("Last token: '%s'\n", last+1);
}

Demo.

Upvotes: 23

hlscalon
hlscalon

Reputation: 7552

Just use another variable to store last token before it gets null

char s[] = "some/very/big/string";
char * token, * last;
last = token = strtok(s, "/");
for (;(token = strtok(NULL, "/")) != NULL; last = token);
printf("%s\n", last);

Upvotes: 4

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