CODEWITHSUNDEEP
linuxbash
BaBazinga
BaBazinga

Reputation: 159

Simple int condition in Bash doesn't make sense

x=23;
y=223;
if [[ $x < $y ]]
then
    echo "TRUE"
else
    echo "FALSE"
fi

So this always print FALSE even thought 23 is clearly less than 223. I am new to bash so I might be missing something obvious. I tried substituting $x and $y with their actually value and that means to work fine. Please send help

Upvotes: 1

Views: 18

Answers (1)

Barmar
Barmar

Reputation: 781096

< performs lexicographic ordering of strings. To get numeric ordering, use -lt.

x=23;
y=223;
if [[ $x -lt $y ]]
then
    echo "TRUE"
else
    echo "FALSE"
fi

Or you can use an arithmetic expression instead of a conditional expression:

if (( $x < $y ))

Upvotes: 2

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