CODEWITHSUNDEEP
python
osupb37
osupb37

Reputation: 33

Parse lines into individual segments - python

I'm new to python and having issues working with a text file. The text file structure being used is shown. What I'm trying to do is first split the two polylines into their own variable and then split each variable into individual coordinates. The end goal is to have it structured as:

polyline 1:
[###, ###] [###, ###]

polyline 2:
[###, ###] [###, ###]

Text file structure:

Polyline;

1: ###,###; ###,###

2: ###,###; ###,###; ###,###

The code I've tried is just working with a single line. While I've been able to split the single line, I have not been able to move to the next step which is to split the line further.

    f=open('txt.txt', 'r')
    pl = []
    for line in f.read().split('\n'):
        if (line.find('1: ') !=-1):
            ln = line.split('1: ')
            print ln
    f.close()

What is the best way to split the line to the end state?

Upvotes: 3

Views: 653

Answers (1)

Kasravnd
Kasravnd

Reputation: 107287

First of all you can use with ... as statement to open a file which will close the file at the end of block , secondly you don't have to read the file and split with \n just use a for loop to loop over your file object.

Also for checking the start with digit number you can us regex and in this case you can use re.match function, then you can split the line with ; and using a list comprehension split another parts with , :

import re
with open('txt.txt') as f:
    for line in f:
        if re.match(r'\d:.*',line):
            ln = [var.split(',') for var in line.split(';')]
            print ln

Upvotes: 3

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