Reputation: 158
So I am trying to create an array and then access the columns by name. So I came up with something like this:
import numpy as np
data = np.ndarray(shape=(3,1000),
dtype=[('x',np.float64),
('y',np.float64),
('z',np.float64)])
I am confused as to why
data.shape
and
data['x'].shape
both come back as (3,1000), this is causing me issues when I'm trying to populate my data fields
data['x'] = xvalues
where xvalues has a shape of (1000,). Is there a better way to do this?
Upvotes: 1
Views: 147
Reputation: 4761
The reason why it comes out the same is because 'data' has a bit more structure than the one revealed by shape.
Example:
data[0][0] returns
:
(6.9182540632428e-310, 6.9182540633353e-310, 6.9182540633851e-310)
while data['x'][0][0]:
returns 6.9182540632427993e-310
so data contains 3 rows and 1000 columns, and the element of that is a 3-tuple.
data['x'] is the first element of that tuple of all combinations of 3 rows and 1000 columns, so the shape is (3,1000) as well.
Upvotes: 1
Reputation: 3496
Just set shape=(1000,)
. The triple dtype will create 3 columns.
Upvotes: 0