Reputation:
I have a 3D matrix and I want to store each 2D component of this in the row of another 2D matrix which has many rows as the 3rd dimension of the 3D matrix.
How can I do this?
Upvotes: 5
Views: 332
Reputation: 35525
That is easily done with MATLABs matrix unrolling syntax:
A=ones(N,M,O);
B=zeros(O,N*M);
for ii=1:size(A,3)
aux=A(:,:,ii); % aux is NxM
B(ii,:)=aux(:); % unroll!
end
(note I called O
the thing you call N
in your pictures)
Upvotes: 1
Reputation: 112759
If you don't mind a little indexing madness...
You can build a linear index with the appropriate shape, which applied on the original array will give the desired result:
B = A(bsxfun(@plus, (1:L*M:L*M*N).', reshape(bsxfun(@plus, (0:L:L*M-1).', 0:L-1),1,[])));
Example:
>> A = randi(10,2,3,4)-1; %// example array; size 2x3x4
>> A
A(:,:,1) =
5 3 2
9 8 9
A(:,:,2) =
8 7 4
9 8 6
A(:,:,3) =
3 4 8
0 4 4
A(:,:,4) =
2 8 8
4 6 7
Result:
>> B
B =
5 3 2 9 8 9
8 7 4 9 8 6
3 4 8 0 4 4
2 8 8 4 6 7
Upvotes: 2
Reputation: 221684
reshape(permute(A,[3 2 1]),size(A,3),[])
Sample run -
>> A
A(:,:,1) =
7 1 7 5
3 4 8 5
9 4 2 6
A(:,:,2) =
7 7 2 4
7 6 5 6
3 2 9 3
A(:,:,3) =
7 7 5 3
3 9 2 8
5 9 2 3
>> reshape(permute(A,[3 2 1]),size(A,3),[])
ans =
7 1 7 5 3 4 8 5 9 4 2 6
7 7 2 4 7 6 5 6 3 2 9 3
7 7 5 3 3 9 2 8 5 9 2 3
Upvotes: 5