CODEWITHSUNDEEP
javatomcatrequestrestful-architectureendpoint
Thilina Sampath
Thilina Sampath

Reputation: 3775

How to sent XML file endpoint url in Restful web service

I need to send the request XML file to {url} as multipart form data. How this do in Restful web service. Before I use in there in,

RequestDispatcher rd = request.getRequestDispatcher("/file/message.jsp");
rd.forward(request, response);

But this isn't sent in specific {url}, How to sent it?

Upvotes: 0

Views: 3132

Answers (3)

Patrick
Patrick

Reputation: 12734

You can use the Jersey Rest Client to send your XML message as post request.

try {
    Client client = Client.create();

    WebResource webResource = client.resource(http://<your URI>);

    // POST method
    ClientResponse response = webResource.accept("multipart/form-data").type("multipart/form-data").post(ClientResponse.class, "<your XML message>");

    // check response status code
    if (response.getStatus() != 200) {
        throw new RuntimeException("Failed : HTTP error code : " + response.getStatus());
    }

    // display response
    String output = response.getEntity(String.class);
    System.out.println("Output from Server .... ");
    System.out.println(output + "\n");
} catch (Exception e) {
     e.printStackTrace();
}

For Jersey Client you can find documentation here:

Jersey REST Client

WebResource

Upvotes: 2

HassanBakri
HassanBakri

Reputation: 91

I don't think web service is best choice for you
you can try native stream and then you can write the header and the body as you like here is sample code to explain my point

Socket socket=new new socket(InetAddress.getByName("stackoverflow.com"), 80);
// just the host and the port
Writer out = new OutputStreamWriter(socket.getOutputStream(),"UTF-8");
            out.write("POST http://" + HOST + ":" + port+ "/ HTTP/1.1\r\n");//here u can insert your end point or the page accepts the xml msg
    out.write("Host: " + HOST + "/ \r\n");
    out.write("Content-type: application/xml,text/xml\r\n");// Accept
    out.write("Content-length: " + req.length() + "\r\n");
    out.write("Accept:application/xml,text/xml\r\n");
    out.write("\r\n");
    // req the Request Body or the xml file to be sent
    out.write(req);//
    out.flush();`

Upvotes: 0

Andr&#233; Blaszczyk
Andr&#233; Blaszczyk

Reputation: 760

If you can do it (depends on your context), using a JAX-RS client is a solution.

Example with Apache CXF :

InputStream inputStream = getClass().getResourceAsStream("/file/message.jsp");
WebClient client = WebClient.create("http://myURL");
client.type("multipart/form-data");
ContentDisposition cd = new ContentDisposition("attachment;filename=message.jsp");
Attachment att = new Attachment("root", inputStream, cd);
client.post(new MultipartBody(att));

Upvotes: 1

Related Questions