CODEWITHSUNDEEP
javascriptif-statementsyntax-error
Ronk
Ronk

Reputation: 225

Why am I getting a Javascript "if" failure?

alert(Tag);  // Tag shows it is set to 0 (ZERO) which is less than 10.

if ( Tag < 10) { alert("adding.."); Tag=Tag+10; }
else { alert("Fail"); }
alert(Tag);

// alert shows me "fail" // and alert shows "0"

So, it says its zero, if statement DOES NOT show it less than 10, and it remains zero.... What am I doing wrong??

Upvotes: 3

Views: 162

Answers (3)

Jeremy Larter
Jeremy Larter

Reputation: 558

http://jsbin.com/honixenopo/edit?js,console

I suspect tag is set to a string with the capital letter o as a type-o.

Upvotes: 0

Cecil Theodore
Cecil Theodore

Reputation: 9939

You need to define Tag first. I am also just incrementing Tag by 1. This can be changed if needed.

var Tag = 0;
if ( Tag < 10) { 
    alert("adding.."); 
    Tag++; 
}
else { 
    alert("Fail"); 
}
alert(Tag);

Upvotes: 1

manonthemat
manonthemat

Reputation: 6251

This works when Tag is actually the number 0.

<script>
var Tag = 0;
alert(Tag);  // Tag shows it is set to 0 (ZERO) which is less than 10.

if ( Tag < 10) { alert("adding.."); Tag=Tag+10; }
else { alert("Fail"); }
alert(Tag);
</script>

Where do you assign Tag its value?

Upvotes: 1

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