CODEWITHSUNDEEP
pythonfloating-pointprecisionmpmath
abcd
abcd

Reputation: 10751

Have I encountered a limit to mpmath's floating-point precision?

mpmath purports to support "arbitrary-precision floating-point arithmetic."

And yet . . .

>>> import mpmath
>>> 1 + mpmath.erf(-5.921)
mpf('1.1102230246251565e-16')
>>> 1 + mpmath.erf(-5.922)  # I expect a smaller positive number here.
mpf('0.0')

Am I missing something? Or is this a fundamental limitation of mpmath?

@jonrsharpe has suggested that the problem is that I've submitted a float to erf. However, the code below shows that this is not the problem:

>>> 1 + mpmath.erf(mpmath.mpf('-5.922'))
mpf('0.0')

Upvotes: 1

Views: 417

Answers (1)

abcd
abcd

Reputation: 10751

The issue in this particular case has to do with mpmath's global precision setting being too low. The default value for prec is

>>> mpmath.mp.prec
53

When I set it to 100, I get the result I was expecting:

>>> 1 + mpmath.erf(-5.922)
mpf('5.5236667058718205581661131647751e-17')

In this case the speed difference isn't noticeable, but note that increasing the precision generally increases the time required to compute the result.

Upvotes: 1

Related Questions