Reputation: 3805
Here is a simple loop
for (i in seq(1,30)) {
mdl<-i
}
How do I get 30 mdl
rather than just one mdl
(which is happening because within the loop, mdli
is being replaced by mdli+1
at every iteration. What I want is to have 30 mdl
perhaps with names like mdl1
, mdl2
....mdl30
I tried this:
for (i in seq(1,30)) {
mdli<-i
}
But if I type mdl1
, it says mdl1 not found
whereas typing mdli
gives me the value of i=5
Thank you
Upvotes: 1
Views: 135
Reputation: 4995
You can specify your store variable beforhand without determine how many values it shall store. If you want for each value a seperate variable take a look at the paste
function.
x<- NULL
for (i in 1:10){
x[i] <- i*2
}
*edit: The comment above is right. This way is not the most efficent one. But I still use it when computation time is not an issue.
Upvotes: 1