CODEWITHSUNDEEP
c#lambdaternary
shinriyo
shinriyo

Reputation: 344

How to call function which has action by using ternary operator?

I defined the function

public void HogeFunc(Action<Bar> act)
{
    this.act = act;
}

If I call HogeFunc, it works.

if(isFuga)
{
    hogeClass.HogeFunc(null);
}
else
{
    hogeClass.HogeFunc(this.MyFunc);
}

But, I'd like to call HogeFunc by using ternary operator.

So, I wrote like below

try1

hogeClass.HogeFunc(isFuga ? null : this.MyFunc);

try2

hogeClass.HogeFunc((i)=>{return isFuga ? null : this.MyFunc;});

But, there didn't work...

Could you tell me how to?

Upvotes: 0

Views: 309

Answers (4)

ipavlu
ipavlu

Reputation: 1649

It is very simple, you are just mixing parts of the ternary operation and you need type cast.

Following code:

if(isFuga)
{
    hogeClass.HogeFunc(null);
}
else
{
    hogeClass.HogeFunc(this.MyFunc);
}

can be rwritten as here:

hogeClass.HogeFunc(isFuge ? (Action<Bar>)null : (Action<Bar>)this.MyFunc);

or here:

hogeClass.HogeFunc(isFuge ? (Action<Bar>)null : (Action<Bar>)(x_bar => 
{
   this.MyFunc(x_bar);
}));

Upvotes: 0

displayName
displayName

Reputation: 14379

Your first try looks correct to me, however you can also call like:

isFuga ? hogeClass.HogeFunc(null) : hogeClass.HogeFunc(this.MyFunc);

Upvotes: 1

ThiagoPXP
ThiagoPXP

Reputation: 5462

In order to use ternary operators in C#, both results MUST return the same object type.

Try casting null to the same return type of this.MyFunc

Upvotes: 1

Keith Nicholas
Keith Nicholas

Reputation: 44288

ternary operators need to return the same type from both options.

Upvotes: 1

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