CODEWITHSUNDEEP
iosswiftxcode7
Ganesh Kumar
Ganesh Kumar

Reputation: 1651

Type of expression is ambiguous without more context

if personal_id == nil {

        if let err = SD.executeChange("INSERT INTO personal_info(user_id, fname, lname, gender, dob, country_code, phone, created_at) values (?,?,?,?,?,?,?,?)", withArgs: [email, fname, lname, gender, date, country_code, phone, strDate]) {
                let alert = UIAlertView()
                alert.title = "Table"
                alert.message = "Error inserting"
                alert.addButtonWithTitle("Ok")
                alert.show()
        } else{
            let alert = UIAlertView()
            alert.title = "Table"
            alert.message = "successfully inserted"
            alert.addButtonWithTitle("Ok")
            alert.show()
        }
    } else {
        if let err_update = SD.executeChange("UPDATE personal_info SET fname = ?, lname = ?, gender = ?, dob = ?, country_code = ?, phone = ?, updated_at = ? WHERE personal_info_id = ?", withArgs: [fname, lname, gender, date, country_code, phone, strDate, personal_id!]) {
                let alert = UIAlertView()
                alert.title = "Table"
                alert.message = "Error updating"
                alert.addButtonWithTitle("Ok")
                alert.show()
        } else {
                let alert = UIAlertView()
                alert.title = "Table"
                alert.message = "Record updated"
                alert.addButtonWithTitle("Ok")
                alert.show()
        }
    }

I have recently updated to Xcode 7.0.1 from 6.4. Now I am having a lot of errors. This code shows an error:

Type of expression is ambiguous without more context

in the place of withArgs: []

Here's executeChange method signature:

public static func executeChange(sqlStr: String, withArgs: [AnyObject]) -> Int?

Upvotes: 2

Views: 1489

Answers (1)

Vladimir Kofman
Vladimir Kofman

Reputation: 1993

Since withArgs method parameter defined as

withArgs: [AnyObject]

you can't have Optionals in that array. To make it work you'll have to unwrap them first.

Upvotes: 2

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