CODEWITHSUNDEEP
c#.netregex
madan
madan

Reputation: 783

Find all the words which contain numeric values using regex?

In my Dot net Application I have to find all the words which contain alphabets and numeric values,I tried to find but fail to find proper answer I have (?=.\d)\w+ regex but it returns 45 as valid. Below is my sample list in which bold are right words and other are false words

I cannot put [a-zA-Z] because my text may contain other than English language ex. โครงการสาวอีสานก็5000บาท.

Upvotes: 1

Views: 122

Answers (5)

w.b
w.b

Reputation: 11228

This also works:

string pattern = @"^(?=\D*\d)(?=\d*\D)\w+$";

To check:

var inputs = new List<string> { "madan45", "45madan", "mad45an", "Madan", "45" };

foreach (var str in inputs)
    Console.WriteLine($"{str} - {Regex.IsMatch(str, pattern)}");

output:

//  madan45 - True
//  45madan - True
//  mad45an - True
//  Madan - False
//  45 - False

Upvotes: 1

vks
vks

Reputation: 67968

(?:^|(?<=\s))(?=\S*\d)(?=\S*(?!\s)\D)\S+(?=\s|$)

Try this.See demo.

https://regex101.com/r/cJ6zQ3/15

Upvotes: 2

Kerwin
Kerwin

Reputation: 1212

^(?!(\d+|[A-z]+)$)\w+$

(\d+|[A-z]+)$:all letter or all digit.

(?!(\d+|[A-z]+)$):Negative Lookahead - Assert that it is impossible to match all letter or all digit.

Upvotes: 2

Mariano
Mariano

Reputation: 6511

all the words which contain alphabets and numeric values

fail to find proper answer I have (?=.\d)\w+

You were close. The lookahead should match any word character before the digit to meet the numeric condition. And then, in the main pattern, require a letter:

Regex:

(?=\w*\d)\d*[A-Za-z]\w*

regex101 Demo

  1. Lookahead
    • \w* Any word character: [A-Za-z0-9_]
    • \d Requires 1 digit.
  2. Main pattern
    • \d* Any digits preceding a letter.
    • [A-Za-z] Requires 1 letter.
    • \w* Rest of the word

Upvotes: 1

MrSpt
MrSpt

Reputation: 1073

(?:\d+[a-z]|[a-z]+\d)[a-z\d]*

This Reg Ex should work for your requirements.

Upvotes: 1

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