CODEWITHSUNDEEP
swiftswift2option-type
Harsh Vira
Harsh Vira

Reputation: 3

How to solve this error in Swift2?

Playground execution failed: MyPlayground.playground:19:33: error: cannot find an initializer for type 'Int' that accepts an argument list of type '(String)' var languagesLearnedNum: Int? = Int(languagesLearned) ^

var languagesLearned: String = "3"
var languagesLearnedNum: Int? = Int(languagesLearned)
if let num = languagesLearnedNum {
    println("It is a Number")
}else {
    println("It is not a Number")
}

Upvotes: 0

Views: 131

Answers (1)

Arthur Gevorkyan
Arthur Gevorkyan

Reputation: 2107

Use languagesLearned.toInt(). However, you're not using Swift 2.0 as if you were, you would be able to use Int(languagesLearned) but not println().

Upvotes: 1

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