CODEWITHSUNDEEP
javascriptjquery
Weidling C
Weidling C

Reputation: 55

JQuery function not found

following code:

// also tried function getDeletedDates()
var getDeletedDates = function()
{
    var s = new Array();

    $(".deleted").each(function(i, e) {
        s.push($(e).attr("data-day"));
    });
};

    $(function()
    {
        $("#delete_send").click(function() {
            alert("drin");
            $.ajax({
                  url: "delete.php",
                  type: "POST",
                  data: ({deleteDates : getDeletedDates()}),
                  dataType: "json",
                  success: function(msg){
                     alert(msg);
                  },
                  beforeSend: function(){
                      alert("Lösche folgende Urlaubstage: "+ getDeletedDates().join(", "));
                  },
                  error: function(x, s, e) {
                      alert("Fehler: " + s);
                  }
               }
            );
        });
    });

But i come into beforeSend() he always says "getDeletedDates() undefined" Why is this, i declared the function in global scope?

thanks in advance.

Upvotes: 4

Views: 1150

Answers (2)

Matthew Abbott
Matthew Abbott

Reputation: 61617

Your function doesn't return anything, so the result will be undefined. Change the method to return the array.

UPDATE:

When you do getDeletedDates() it is evaluated to undefined, because of the lack of return result. This is why getDeletedDates() is undefined is the error message.

Upvotes: 5

Prutswonder
Prutswonder

Reputation: 10074

You are calling your function, but the function is defined as a variable/pointer and doesn't return anything. The following modification should work (not tested):

function getDeletedDates()
{
    var s = new Array();

    $(".deleted").each(function(i, e) {
        s.push($(e).attr("data-day"));
    });

    return s;
};

Upvotes: 2

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