CODEWITHSUNDEEP
javaregex
Sheena Tyagi
Sheena Tyagi

Reputation: 341

How to remove a numeric value at specific position in a String

I want to remove a numeric value from a specific position position. I have used a regex but it deletes every numeric value from the String.

I have these Strings:

Draft1(admin)
Draft2(adminn)
Draft21(admin23)
Draft112(admin211)

And I want these strings as: 

Draft(admin)
Draft(adminn)
Draft(admin23)
Draft(admin211)

currently I've used regex: 

name = name.replaceAll("\\d", "");

which replaces all the numeric values and I get something like:

Draft(admin)

Upvotes: 1

Views: 128

Answers (4)

Pankaj Saboo
Pankaj Saboo

Reputation: 1185

This works

public static void main(String[] args) {
    String name = "Draft112(admin211)";
    name = name.replaceAll("\\d+(?=\\()","");
    System.out.println(name);
}

Upvotes: 0

ABHISHEK RANA
ABHISHEK RANA

Reputation: 327

You could try this

class String111
{
public static void main(String args[])
{
String s1="Draft1(admin)";
String s2="Draft21(admin23)";

System.out.println(s1.substring(0,s1.indexOf('(')).replaceAll("\\d", "")+s1.substring(s1.indexOf('('),s1.length()));

System.out.println(s2.substring(0,s2.indexOf('(')).replaceAll("\\d", "")+s2.substring(s2.indexOf('('),s2.length()));
}
}

Upvotes: 0

Stanislav
Stanislav

Reputation: 28106

You can simply use String#replaceFirst with regex like (?i)(?<=Draft)\d+ to delete this digits:

name = name.replaceFirst("(?i)(?<=Draft)\\d+","");

Where:

(?i) makes regex caseinsensitive, so the Draft could be even DRAFT or draft

(?<=Draft) is lookbehind for Draft word, which asserts that what immediately precedes the current position in the string is Draft

\\d+ are one or more digit to be replaced

Upvotes: 1

vks
vks

Reputation: 67968

(?<=Draft)\\d+\\b

You can use this and replace by empty string.The lookbehind will make sure it replace only numbers after Draft.

Upvotes: 0

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