CODEWITHSUNDEEP
xsltxslt-2.0
user3872094
user3872094

Reputation: 3351

Get a specific processing instruction

I've the below XML.

<?xpp /MAIN?>
<?xpp MAIN;1;0;0;0;619;0;0?>
<section>
  <title>Introduction</title>
  <para>
    para<superscript>1</superscript>
    <?xpp foot;art6_ft1;suppress?>
    <?xpp FOOT;art6_ft1;1?>
    <footnote label="1" id="art6_ft1">
      <para>
        data
      </para>
    </footnote>
    <?xpp /FOOT?>
    The data
  </para>
</section>

Here I want to get the processing instruction containing MAINin it, but i'm unable to know how to get it.

I'm trying the below XSLT.

<xsl:template match="/">
        <html>
            <head>

            </head>
            <body>
                <xsl:if test="//footnote">
                        <xsl:apply-templates select="//processing-instruction('xpp')[not(ancestor::toc)]| //footnote" mode="footnote"/>
                </xsl:if>
            </body>
        </html>
    </xsl:template>
.
.
.
.
.
.
.
<xsl:template match="processing-instruction('xpp')" mode="footnote">
    <xsl:if test="following::footnote[1][preceding::processing-instruction('xpp')[1] = current()]">
    <xsl:variable name="pb" select="."/>
        <xsl:processing-instruction name="pb">
            <xsl:text>label='</xsl:text>
            <xsl:value-of select="$pb"/>
            <xsl:text>'</xsl:text>
            <xsl:text>?</xsl:text>
        </xsl:processing-instruction>
    </xsl:if>
</xsl:template>

running this i'm getting <?xpp FOOT;art6_ft1;1?> picked, but i want <?xpp MAIN;1;0;0;0;619;0;0?> to be picked, please let me know how can i do this.

Thanks

Upvotes: 0

Views: 355

Answers (1)

har07
har07

Reputation: 89325

"Here I want to get the processing instruction containing MAIN in it, but i'm unable to know how to get it."

You can use the following XPath expression to match processing instruction named xpp having data contains text "MAIN" :

processing-instruction('xpp')[contains(.,'MAIN')]

Upvotes: 1

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