Reputation: 27592
Is it possible to define the default value for variables of a template function in C++?
Something like below:
template<class T> T sum(T a, T b, T c=????)
{
return a + b + c;
}
Upvotes: 12
Views: 21964
Reputation: 4892
Yes!
However you should at least have an idea about what T could be or it's useless.
You can't set the default value of template parameters for functions, i.e. this is forbidden:
template<typename T=int> void f(T a, T b);
Upvotes: 0
Reputation: 17757
Try this:
template<class T> T sum(T a, T b, T c=T())
{
return a + b + c;
}
You can also put in T(5) if you are expecting an integral type and want the default value to be 5.
Upvotes: 13
Reputation: 4391
Yes you can define a default value.
template <class T>
T constructThird()
{
return T(1);
}
template <class T>
T test(T a,
T b,
T c = constructThird<T>())
{
return a + b + c;
}
Unfortunately constructThird cannot take a and b as arguments.
Upvotes: 2
Reputation: 208323
It all depends on the assumptions that you can do about the type.
template <typename T> T sum( T a, T b, T c = T() ) { return a+b+c; }
template <typename T> T sum2( T a, T b, T c = T(5) ) { return a+b+c; }
The first case, it only assumes that T
is default constructible. For POD types that is value inititalization (IIRC) and is basically 0
, so sum( 5, 7 )
will call sum( 5, 7, 0 )
.
In the second case you require that the type can be constructed from an integer. For integral types, sum( 5, 7 )
will call sum( 5, 7, int(5) )
which is equivalent to sum( 5, 7, 5 )
.
Upvotes: 7
Reputation: 38118
Yes, there just needs to be a constructor for T
from whatever value you put there. Given the code you show, I assume you'd probably want that argument to be 0
. If you want more than one argument to the constructor, you could put T(arg1, arg2, arg3)
as the default value.
Upvotes: 1