Reputation: 73
I'm trying to create a deck of 52 cards with the 4 suits: spades, hearts, clubs, and diamonds. I tried to create this for loop in my Deck class but seem to be running into some problems regarding actually getting the program to do what I want. I'm thinking maybe I could do 4 for loops as the assignment hinted at, but is it possible to use if/else-ifs to create 4 suits within the deck?
class Deck
{
private Card[] cards;
public Deck()
{
cards = new Card[52];
int check = 0;
for (int suitVal = 1; suitVal < 4; suitVal++)
{
for (int rankVal = 1; rankVal < 14; rankVal++)
{
if(suitVal == 1)
{
cards[check] = new Card(rankVal, "Spades");
}
else if (suitVal == 2)
{
cards[check] = new Card(rankVal, "Hearts");
}
else if (suitVal == 3)
{
cards[check] = new Card(rankVal, "Clubs");
}
else if (suitVal == 4)
{
cards[check] = new Card(rankVal, "Diamonds");
}
}
}
}
Upvotes: 1
Views: 21018
Reputation: 117057
You could do it these ways:
class Deck
{
private Card[] cards;
public Deck()
{
cards =
new [] { "Spades", "Hearts", "Clubs", "Diamonds", }
.SelectMany(
suit => Enumerable.Range(1, 13),
(suit, rank) => new Card(rank, suit))
.ToArray();
}
}
Or:
class Deck
{
private Card[] cards;
public Deck()
{
var query =
from suit in new [] { "Spades", "Hearts", "Clubs", "Diamonds", }
from rank in Enumerable.Range(1, 13)
select new Card(rank, suit);
cards = query.ToArray();
}
}
Or:
class Deck
{
private Card[] cards;
public Deck()
{
cards = new Card[52];
var index = 0;
foreach (var suit in new [] { "Spades", "Hearts", "Clubs", "Diamonds", })
{
for (var rank = 1; rank <= 13; rank++)
{
cards[index++] = new Card(rank, suit);
}
}
}
}
Upvotes: 2
Reputation: 1552
Yes, it is possible. There are 13 cards and 4 suits. The idea is that for each suit, you create 13 cards with of said suit. The pseudo code is pretty much what you have already got:
for each of the four suits
loop 13 times for said suit
Here are the problems with your code:
1- Your check
variable is never incremented, so you always overwrite the card on the position 0; It should increment after every card inserted (inner loop)
2- Your outter loop only runs 3 times (i = 1, i = 2, i = 3), and there are 4 suits.
Let me know if you need more help.
Upvotes: 6