Reputation: 96791
Consider following code:
union U
{
int a;
float b;
};
int main()
{
U u;
int *p = &u.a;
*(float *)p = 1.0f; // <-- this line
}
We all know that addresses of union fields are usually same, but I'm not sure is it well-defined behavior to do something like this.
So, question is: Is it legal and well-defined behavior to cast and dereference a pointer to union field like in the code above?
P.S. I know that it's more C than C++, but I'm trying to understand if it's legal in C++, not C.
Upvotes: 11
Views: 1990
Reputation: 63872
All members of a union must reside at the same address, that is guaranteed by the standard. What you are doing is indeed well-defined behavior, but it shall be noted that you cannot read from an inactive member of a union using the same approach.
Note: Do not use c-style casts, prefer
reinterpret_cast
in this case.
As long as all you do is write to the other data-member of the union
, the behavior is well-defined; but as stated this changes which is considered to be the active member of the union
; meaning that you can later only read from that you just wrote to.
union U {
int a;
float b;
};
int main () {
U u;
int *p = &u.a;
reinterpret_cast<float*> (p) = 1.0f; // ok, well-defined
}
Note: There is an exception to the above rule when it comes to layout-compatible types.
The question can be rephrased into the following snippet which is semantically equivalent to a boiled down version of the "problem".
#include <type_traits>
#include <algorithm>
#include <cassert>
int main () {
using union_storage_t = std::aligned_storage<
std::max ( sizeof(int), sizeof(float)),
std::max (alignof(int), alignof(float))
>::type;
union_storage_t u;
int * p1 = reinterpret_cast< int*> (&u);
float * p2 = reinterpret_cast<float*> (p1);
float * p3 = reinterpret_cast<float*> (&u);
assert (p2 == p3); // will never fire
}
n3797
) say?9.5/1 Unions [class.union]
In a union, at most one of the non-static data members can be active at any time, that is, the value of at most one of the non-static dat amembers ca nbe stored in a union at any time. [...] The size of a union is sufficient to contain the largest of its non-static data members. Each non-static data member is allocated as if it were the sole member of a struct. All non-static data members of a union object have the same address.
Note: The wording in C++11 (n3337) was underspecified, even though the intent has always been that of C++14.
Upvotes: 7
Reputation: 57739
Yes, it is legal. Using explicit casts, you can do almost anything.
As other comments have stated, all members in a union
start at the same address / location so casting a pointer to a different member is pointless.
The assembly language will be the same. You want to make the code easy to read so I don't recommend the practice. It is confusing and there is no benefit.
Also, I recommend a "type" field so that you know when the data is in float
format versus int
format.
Upvotes: 3