CODEWITHSUNDEEP
bashshellsh
Jon Abraham
Jon Abraham

Reputation: 955

How to handle whitespace in shell?

Input File 

      name;x1;x2
    jon,doe;10;20
    sam,smith;11;21

This is what i have tried so far

awk 'BEGIN {print "name\tx1\tx2\tAvg"} {s+=$2} {k+=$3} {print $1,"\t",$2,"\t",$3,"\t",($2+$3)/2} END {print s/2,k/2}' input.txt

I am trying to find the average of rows and columns from an input file but at the end i am getting one zero that i don't need and i believe that is due to white space. Can someone help me how to handle white space here ?

The expected output should be :

name;x1;x2 Average 
jon,doe;10;20 15
sam,smith;11;21 16
Average 10.5 20.5

Upvotes: 0

Views: 68

Answers (1)

John1024
John1024

Reputation: 113814

The default input field separator for awk is whitespace. That doesn't work for your file where the field separator is a semicolon. To fix that, use the -F\; option. With a few other minor changes, try:

$ awk -F';' '{sub(/^ +/,"");} NR==1 {print $0, "Avg";next} {s+=$2} {k+=$3} {print $0,($2+$3)/2} END {print "Ave",s/(NR-1),k/(NR-1)}' OFS='\t' input.txt
name;x1;x2      Avg
jon,doe;10;20   15
sam,smith;11;21 16
Ave     10.5    20.5

The sample output in the question and as above has a mix of semicolons and whitespace for field separators. If you want to consistently use semicolons:

$ awk -F';' '{sub(/^ +/,"");} NR==1 {print $0, "Avg";next} {s+=$2} {k+=$3} {print $0,($2+$3)/2} END {print "Ave",s/(NR-1),k/(NR-1)}' OFS=';' input.txt
name;x1;x2;Avg
jon,doe;10;20;15
sam,smith;11;21;16
Ave;10.5;20.5

Upvotes: 2

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