Reputation: 155
Here's what I am trying to do. I have a spring batch job which triggers a bean with multiple properties. I want these properties to be divided into separate beans for organizational purposes.
So I currently have this:
<bean id="runSQL" class="Tasklet"
scope="step">
<property name="sourceSQL"
value="SQL STATEMENT HERE" />
<property name="targetSQL"
value="SQL STATEMENT HERE"></property>
<property name="filePath" value="#{jobParameters['OUTPUT.FILE.PATH']}"> </property>
</bean>
but I basically want this (not working due to lack of class definition and I don't know if #{souce.sourceSQL} is a valid way of grabbing bean properties):
<bean id="runSQL" class="Tasklet"
scope="step">
<property name="sourceSQL"
value="#{source.sourceSQL}" />
<property name="targetSQL"
value="#{target.targetSQL}"></property>
<property name="filePath" value="#{jobParameters['OUTPUT.FILE.PATH']}"> </property>
</bean>
<bean id="sourceSQL" class="Class not needed"
scope="step">
<property name="sourceSQL"
value="SQL STATEMENT HERE" />
</property>
</bean>
<bean id="targetSQL" class="Class not needed"
scope="step">
<property name="sourceSQL"
value="SQL STATEMENT HERE" />
</property>
</bean>
I have tried to reference the beans traditionally with
<ref bean="someBean"/>
but my Tasklet isn't designed to receive a bean, just the property values and I would prefer to leave the Tasklet as is. How do I get around this or alternative ways of storing this data for the beans?
Upvotes: 1
Views: 1915
Reputation: 1626
You're on the right track with #{...}
. If you want to reference a bean, stick a @
in front of the Spring bean ID, for example #{@sourceSQL.sourceSQL}
and #{@targetSQL.sourceSQL}
.
See the documentation for the Spring Expression language.
Upvotes: 1