Reputation: 439
I need to convert a incoming json file to XML.
I am using the following code to achieve the requirement. I am using Newtonsoft Json Converter
XmlDocument doc = (XmlDocument)JsonConvert.DeserializeXmlNode(json);
And the input file is
{"menu": { "id": "file", "value": "File", "popup": { "menuitem": [ {"value": "New", "onclick": "CreateNewDoc()"}, {"value": "Open", "onclick": "OpenDoc()"}, {"value": "Close", "onclick": "CloseDoc()"} ] }}}
And the output I am getting is
<menu><id>file</id><value>File</value><popup><menuitem><value>New</value><onclick>CreateNewDoc()</onclick></menuitem><menuitem><value>Open</value><onclick>OpenDoc()</onclick></menuitem><menuitem><value>Close</value><onclick>CloseDoc()</onclick></menuitem></popup></menu>
So here the attributes are generating as Nodes.
Thanks in Advance
Upvotes: 3
Views: 541
Reputation: 116990
From Converting between JSON and XML:
Conversion Rules
- Attributes are prefixed with an @ and should be at the start of the object.
Thus you could use Linq to JSON to modify all JSON properties with primitive values and prepend an @
character to their names. Note that, since your file will be "in MB's", you should avoid loading to a temporary string and instead stream the file contents in directly:
// Load the JObject directly from a file
using (var streamReader = File.OpenText(fileName))
using (var jsonReader = new JsonTextReader(streamReader))
{
obj = JObject.Load(jsonReader);
}
// Rename all properties with primitive values (string, number, boolean, null) to begin with "@"
foreach (var o in obj.Descendants().OfType<JObject>())
{
// Attributes must appear first in the JObject's property list.
int insertIndex = 0;
foreach (var property in o.Properties().Where((p => p.Value is JValue && !p.Name.StartsWith("@"))).ToList())
{
property.Remove();
((IList<JToken>)o).Insert(insertIndex++, new JProperty("@" + property.Name, property.Value));
}
}
// Convert to XmlDocument
XmlDocument doc;
using (var reader = obj.CreateReader())
{
doc = (XmlDocument)JsonExtensions.DeserializeXmlNode(reader);
}
Using the helper methods:
public static class JsonExtensions
{
public static XmlDocument DeserializeXmlNode(JsonReader reader)
{
return DeserializeXmlNode(reader, null, false);
}
public static XmlDocument DeserializeXmlNode(JsonReader reader, string deserializeRootElementName, bool writeArrayAttribute)
{
var converter = new Newtonsoft.Json.Converters.XmlNodeConverter() { DeserializeRootElementName = deserializeRootElementName, WriteArrayAttribute = writeArrayAttribute };
var jsonSerializer = JsonSerializer.CreateDefault(new JsonSerializerSettings { Converters = new JsonConverter[] { converter } });
return (XmlDocument)jsonSerializer.Deserialize(reader, typeof(XmlDocument));
}
}
This produces the output:
<menu id="file" value="File"> <popup> <menuitem value="New" onclick="CreateNewDoc()" /> <menuitem value="Open" onclick="OpenDoc()" /> <menuitem value="Close" onclick="CloseDoc()" /> </popup> </menu>
Upvotes: 2
Reputation: 1416
You should append @
before attribute names.
Like this:
{"menu": { "@id": "file", "@value": "File", "popup": { "menuitem": [ {"@value": "New", "@onclick": "CreateNewDoc()"}, {"@value": "Open", "@onclick": "OpenDoc()"}, {"@value": "Close", "@onclick": "CloseDoc()"} ] }}}
This will create the following XML:
<menu id="file" value="File">
<popup>
<menuitem value="New" onclick="CreateNewDoc()" />
<menuitem value="Open" onclick="OpenDoc()" />
<menuitem value="Close" onclick="CloseDoc()" />
</popup>
</menu>
If you do not have control over JSON then you can modify it programmatic before converting into XML like this:
json = json.Replace("id", "@id").Replace("value", "@value").Replace("onclick", "@onclick");
Or you can transform XML after conversion using XSLT.
Upvotes: 2