Reputation: 26303
new Set(['b', 'a', 'c']).sort()
throws TypeError: set.sort is not a function
. How can I sort a Set
to ensure a particular iteration order?
Upvotes: 146
Views: 126017
Reputation: 148
The .sort function is a higher order function which means it can have another function inside. First of all only .sort() may work with characters or strings but it will give bugs for numbers. I have discussed sets in my video along with sort function. I hope you understand it. https://www.youtube.com/watch?v=ztw4Gh8eogw
//This is sort() for getting numbers in ascending order:
const setC = new Set(([58,12,11,10,5,32]).sort((a,b)=>a -b));
//This is sort() for getting numbers in descending order:
const setC = new Set(([58,12,11,10,5,32]).sort((a,b)=>b -a));
//This is sort() for strings
const setD=new Set((['mangoes','bananas', 'apples','oranages']).sort());
// This is sort() for characters
const setD=new Set((['m', 'b', 'a', 'r']).sort());
You can convert the set to an array too and then sort it but that is not
required in your case.
const arrayofsetA = Array.from(setA);
//for strings or characters
arrayofsetA.sort();
//for numbers or floating point numbers
arrayofsetA.sort((a,b) => a-b);
Upvotes: 0
Reputation: 630
the simplest way to do it as.
console.log(new Set(['b', 'a', 'c'].sort()))
//Set(3) {"a", "b", "c"}
Upvotes: 0
Reputation: 3913
In some cases it may be preferable to "sort" the set in-place, similar to array.sort()
, it can be done like this:
function sortSet(set) {
const entries = [];
for (const member of set) {
entries.push(member);
}
set.clear();
for (const entry of entries.sort()) {
set.add(entry);
}
return set;
};
sortSet(new Set([3,2,1]))
// => Set(3) { 1, 2, 3 }
Upvotes: 5
Reputation: 276496
A set is not an ordered abstract data structure.
A Set
however always has the same iteration order - element insertion order [1], so when you iterate it (by an iterating method, by calling Symbol.iterator
, or by a for.. of loop) you can always expect that.
You can always convert the set to an array and sort that.
Array.from(new Set(["b","a","c"])).sort();
[...(new Set(["b","a","c"]))].sort(); // with spread.
[1] forEach
and CreateSetIterator
Upvotes: 230