Reputation: 53
I have a simple 4x2 html table that contains information about a property.
I'm trying to extract the value 1972
, which is under the column heading of Year Built
. If I find all the tags td
, how do I extract the index of the tag that contains the text Year Built
?
Because once I find that index, I can just add 4
to get to the tag that contains the value 1972
.
Here is the html:
<table>
<tbody>
<tr>
<td>Building</td>
<td>Type</td>
<td>Year Built</td>
<td>Sq. Ft.</td>
</tr>
<tr>
<td>R01</td>
<td>DWELL</td>
<td>1972</td>
<td>1166</td>
</tr>
</tbody>
</table>
For example I know that if my input is index 2
and my output is text of that tag Year Built
, I can just do this:
from bs4 import BeautifulSoup
soup = BeautifulSoup(myhtml)
td_list = soup.find_all('td')
print td_list[2].text
But how do I use input of text Year Built
to get output of index 2
?
Upvotes: 4
Views: 17727
Reputation: 1752
If your table has a static scheme, it is better using row and column indexes. Try this:
rows = soup.find("table").find("tbody").find_all("tr")
print rows[1].find_all("td")[2].get_text()
Alternatively if you just want to find index number of the tag containing "Year Built":
from bs4 import BeautifulSoup
soup = BeautifulSoup(myhtml)
td_list = soup.find_all('td')
i = 0
for elem in td_list:
if elem.text == 'Year Built':
ind = i
i += 1
print td_list[ind].text
Upvotes: 5
Reputation: 356
Convert it to dict and get the value:
from bs4 import BeautifulSoup
table_data = [[cell.text for cell in row("td")] for row in BeautifulSoup(myhtml)("tr")]
dict = dict(zip(table_data[0], table_data[1]))
print dict['Year Built']
Upvotes: 3
Reputation: 215
Your content is stored in filename.
Please try:
In [3]: soup = BeautifulSoup(open("filename"))
In [4]: print soup.find_all('td')[2].string
Year Built
Upvotes: 0