Reputation: 9538
I'm changing the image src of an image node. I want to be able to make sure that it's changed before executing somecode. How would i do that?
right now i have
function changePic(imgNode, newPic, desc){
var descNode = $("#description");
$(imgnode).fadeTo(500, 0, function(){
$(imgnode).attr("src", newPic);
$(imgnode).attr("alt", desc)
descNode.text(desc);
$(imgnode).fadeTo(500, 1);
});
}
Works great if the server's fast/ a local server. Works terribly if the server's slow, where the image will fade back in before changing...
any idea?
Edit: I'm loading the image when changePic is called. Any better ways to do it?
More: Also why is it not a good idea to put the last line,
$(imgnode).fadeTo(500, 1);
, outside of the callback function?
Upvotes: 1
Views: 1221
Reputation: 2858
Preload the image, but to be sure it's completely loaded, use the .load() event.
Quote:
The load event is sent to an element when it and all sub-elements have been completely loaded. This event can be sent to any element associated with a URL: images, scripts, frames, iframes, and the window object.
And don't miss this line:
It is possible that the load event will not be triggered if the image is loaded from the browser cache. To account for this possibility, we can use a special load event that fires immediately if the image is ready. event.special.load is currently available as a plugin.
I put together an example of how I think you want it to work. I switch between three images I found through Google Images. I bind the load event before I change the src of the image to be sure it's triggered. http://jsfiddle.net/xdjjR/1/
Upvotes: 2
Reputation: 2657
I guess, you can preload image in hidden elements, so that it's loaded with other html. When the source changed such image should be shown immediately.
Upvotes: 1