Reputation: 13
I have a list of values and their aggregated lengths of all their occurrences as an array.
Ex: If my sentence is
"I have a cat. The cat looks very cute"
My array looks like
Array((I,1), (have,4), (a,1), (cat,6), (The, 3), (looks, 5), (very ,4), (cute,4))
Now I want to compute the average length of each word. i.e the length / number of occurrences.
I tried to do the coding using Scala as follows:
val avglen = arr.reduceByKey( (x,y) => (x, y.toDouble / x.size.toDouble) )
I'm getting an error as follows at x.size
error: value size is not a member of Int
Please help me where I'm going wrong here.
Upvotes: 1
Views: 4835
Reputation: 18042
After your comment I think I got it:
val words = sc.parallelize(Array(("i", 1), ("have", 4),
("a", 1), ("cat", 6),
("the", 3), ("looks", 5),
("very", 4), ("cute", 4)))
val avgs = words.map { case (word, count) => (word, count / word.length.toDouble) }
println("My averages are: ")
avgs.take(100).foreach(println)
Supposing you have a paragraph with those words and You want to calculate the mean size of the words of the paragraph.
In two steps, with a map-reduce
approach and in spark-1.5.1
:
val words = sc.parallelize(Array(("i", 1), ("have", 4),
("a", 1), ("cat", 6),
("the", 3), ("looks", 5),
("very", 4), ("cute", 4)))
val wordCount = words.map { case (word, count) => count}.reduce((a, b) => a + b)
val wordLength = words.map { case (word, count) => word.length * count}.reduce((a, b) => a + b)
println("The avg length is: " + wordLength / wordCount.toDouble)
I ran this code using an .ipynb connected to a spark-kernel
this is the output.
Upvotes: 0
Reputation: 2442
This is a slightly confusing question. If your data is already in an Array[(String, Int)]
collection (presumably after a collect()
to the driver), then you need not use any RDD
transformations. In fact, there's a nifty trick you can run with fold*()
to grab the average over a collection:
val average = arr.foldLeft(0.0) { case (sum: Double, (_, count: Int)) => sum + count } / arr.foldLeft(0.0) { case (sum: Double, (word: String, count: Int)) => sum + count / word.length }
Kind of long winded, but it essentially aggregates the total number of characters in the numerator and the number of words in the denominator. Run on your example, I see the following:
scala> val arr = Array(("I",1), ("have",4), ("a",1), ("cat",6), ("The", 3), ("looks", 5), ("very" ,4), ("cute",4))
arr: Array[(String, Int)] = Array((I,1), (have,4), (a,1), (cat,6), (The,3), (looks,5), (very,4), (cute,4))
scala> val average = ...
average: Double = 3.111111111111111
If you have your (String, Int)
tuples distributed across an RDD[(String, Int)]
, you can use accumulators to solve this problem quite easily:
val chars = sc.accumulator(0.0)
val words = sc.accumulator(0.0)
wordsRDD.foreach { case (word: String, count: Int) =>
chars += count; words += count / word.length
}
val average = chars.value / words.value
When running on the above example (placed in an RDD
), I see the following:
scala> val arr = Array(("I",1), ("have",4), ("a",1), ("cat",6), ("The", 3), ("looks", 5), ("very" ,4), ("cute",4))
arr: Array[(String, Int)] = Array((I,1), (have,4), (a,1), (cat,6), (The,3), (looks,5), (very,4), (cute,4))
scala> val wordsRDD = sc.parallelize(arr)
wordsRDD: org.apache.spark.rdd.RDD[(String, Int)] = ParallelCollectionRDD[0] at parallelize at <console>:14
scala> val chars = sc.accumulator(0.0)
chars: org.apache.spark.Accumulator[Double] = 0.0
scala> val words = sc.accumulator(0.0)
words: org.apache.spark.Accumulator[Double] = 0.0
scala> wordsRDD.foreach { case (word: String, count: Int) =>
| chars += count; words += count / word.length
| }
...
scala> val average = chars.value / words.value
average: Double = 3.111111111111111
Upvotes: 0
Reputation: 9734
If I understand the problem correctly:
val rdd: RDD[(String, Int) = ???
val ave: RDD[(String, Double) =
rdd.map { case (name, numOccurance) =>
(name, name.length.toDouble / numOccurance)
}
Upvotes: 0