CODEWITHSUNDEEP
pythonbase36
diligar
diligar

Reputation: 423

Python: converting base 10 to base 36

I'm trying to convert decimal to base 36 (...8,9,a,b,c...x,y,z,10,11...) but when I run my code I get a bunch of floats instead of integers.

def trc(n):
    if (n < 0): print(0, end='')
    elif (n<=1): print(n, end='')
    else:
        trc( n / 36 )
        x =(n%36)
        if (x < 10): print(x, end='')
        else: print(chr(x+87), end='')

I based this code off of this.

Upvotes: 1

Views: 4551

Answers (2)

Leo
Leo

Reputation: 35

You could just do this:

def trc(n):
    return(int(str(n), base = 36))

Then print(trc(x)) to get x in base 36. This solution works for any base.

However it doesn't give you the letters of base 36: instead of 'z' it returns 36.

You would need to make a seperate program for that.

It should be good enough in most cases, unless you're working with something like excel that needs the letters.

Upvotes: -1

Blckknght
Blckknght

Reputation: 104792

In Python 3, the / operator does floating point division, even when both arguments are integers. This is a change from Python 2, where dividing two integers would discard the fractional part.

You can explicitly request integer division by using the // operator. The result will be rounded towards negative infinity. Or, since you're also calculating the modulus, you could use divmod to get them both at the same time:

else:
    n, x = divmod(n, 36)
    trc(n)
    if x < 10: # ...

Upvotes: 2

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