CODEWITHSUNDEEP
.netvisual-studiostreamreaderembedded-resource
Me.Close
Me.Close

Reputation: 8741

How to read embedded resource text file

How do I read an embedded resource (text file) using StreamReader and return it as a string? My current script uses a Windows form and textbox that allows the user to find and replace text in a text file that is not embedded. 

private void button1_Click(object sender, EventArgs e)
{
    StringCollection strValuesToSearch = new StringCollection();
    strValuesToSearch.Add("Apple");
    string stringToReplace;
    stringToReplace = textBox1.Text;

    StreamReader FileReader = new StreamReader(@"C:\MyFile.txt");
    string FileContents;
    FileContents = FileReader.ReadToEnd();
    FileReader.Close();
    foreach (string s in strValuesToSearch)
    {
        if (FileContents.Contains(s))
            FileContents = FileContents.Replace(s, stringToReplace);
    }
    StreamWriter FileWriter = new StreamWriter(@"MyFile.txt");
    FileWriter.Write(FileContents);
    FileWriter.Close();
}

Upvotes: 869

Views: 860896

Answers (24)

Save
Save

Reputation: 1423

Most of answers here holds base or full namespace as a constant or iterate over all resources from GetManifestResourceNames to get it. I have much simpler but not perfect solution:

var ns = typeof(Form1).Namespace;
var filename = "MyFile.txt";
using (var s = Assembly.GetExecutingAssembly().GetManifestResourceStream($"{ns}.{filename}"))
using (var sr = new StreamReader(s))
{
    var text = sr.ReadToEnd();
}

// OR
var ns = this.GetType().Namespace;
var filename = "MyFile.txt";
using (var s = Assembly.GetExecutingAssembly().GetManifestResourceStream($"{ns}.{filename}"))
using (var sr = new StreamReader(s))
{
    var text = sr.ReadToEnd();
}

Of course file shold be marked as "Embedded Resource".

Upvotes: 0

dtb
dtb

Reputation: 217293

You can use the Assembly.GetManifestResourceStream Method:

  1. Add the following usings

     using System.IO;
 using System.Reflection;

  2. Set property of relevant file:
    Parameter Build Action with value Embedded Resource

  3. Use the following code

     var assembly = Assembly.GetExecutingAssembly();
 var resourceName = "MyCompany.MyProduct.MyFile.txt";

 using (Stream stream = assembly.GetManifestResourceStream(resourceName))
 using (StreamReader reader = new StreamReader(stream))
 {
     string result = reader.ReadToEnd();
 }

    resourceName is the name of one of the resources embedded in assembly. For example, if you embed a text file named "MyFile.txt" that is placed in the root of a project with default namespace "MyCompany.MyProduct", then resourceName is "MyCompany.MyProduct.MyFile.txt". You can get a list of all resources in an assembly using the Assembly.GetManifestResourceNames Method.

A no brainer astute to get the resourceName from the file name only (by pass the namespace stuff):

string resourceName = assembly.GetManifestResourceNames()
  .Single(str => str.EndsWith("YourFileName.txt"));

A complete example:

public string ReadResource(string name)
{
    // Determine path
    var assembly = Assembly.GetExecutingAssembly();
    string resourcePath = name;
    // Format: "{Namespace}.{Folder}.{filename}.{Extension}"
    if (!name.StartsWith(nameof(SignificantDrawerCompiler)))
    {
        resourcePath = assembly.GetManifestResourceNames()
            .Single(str => str.EndsWith(name));
    }

    using (Stream stream = assembly.GetManifestResourceStream(resourcePath))
    using (StreamReader reader = new StreamReader(stream))
    {
        return reader.ReadToEnd();
    }
}

or as an async extension method:

internal static class AssemblyExtensions
{
    public static async Task<string> ReadResourceAsync(this Assembly assembly, string name)
    {
        // Determine path
        string resourcePath = name;
        // Format: "{Namespace}.{Folder}.{filename}.{Extension}"
        if (!name.StartsWith(nameof(SignificantDrawerCompiler)))
        {
            resourcePath = assembly.GetManifestResourceNames()
                .Single(str => str.EndsWith(name));
        }

        using Stream stream = assembly.GetManifestResourceStream(resourcePath)!;
        using StreamReader reader = new(stream);
        return await reader.ReadToEndAsync();
    }
}

// Usage
string resourceText = await Assembly.GetExecutingAssembly().ReadResourceAsync("myResourceName");

Upvotes: 1552

bytedev
bytedev

Reputation: 9099

public class AssemblyTextFileReader
{
    private readonly Assembly _assembly;

    public AssemblyTextFileReader(Assembly assembly)
    {
        _assembly = assembly ?? throw new ArgumentNullException(nameof(assembly));
    }

    public async Task<string> ReadFileAsync(string fileName)
    {
        var resourceName = _assembly.GetManifestResourceName(fileName);

        using (var stream = _assembly.GetManifestResourceStream(resourceName))
        {
            using (var reader = new StreamReader(stream))
            {
                return await reader.ReadToEndAsync();
            }
        }
    }
}

public static class AssemblyExtensions
{
    public static string GetManifestResourceName(this Assembly assembly, string fileName)
    {
        string name = assembly.GetManifestResourceNames().SingleOrDefault(n => n.EndsWith(fileName, StringComparison.InvariantCultureIgnoreCase));

        if (string.IsNullOrEmpty(name))
        {
            throw new FileNotFoundException($"Embedded file '{fileName}' could not be found in assembly '{assembly.FullName}'.", fileName);
        }

        return name;
    }
}

// To use the code above:
var reader = new AssemblyTextFileReader(assembly);

string text = await reader.ReadFileAsync(@"MyFile.txt");

Upvotes: 2

BullyWiiPlaza
BullyWiiPlaza

Reputation: 19195

This is a class which you might find very convenient for reading embedded resource files from the current Assembly:

using System.IO;
using System.Linq;
using System.Text;
using System.Reflection;

public static class EmbeddedResourceUtils
{
    public static string ReadFromResourceFile(string endingFileName)
    {
        var assembly = Assembly.GetExecutingAssembly();
        var manifestResourceNames = assembly.GetManifestResourceNames();

        foreach (var resourceName in manifestResourceNames)
        {
            var fileNameFromResourceName = _GetFileNameFromResourceName(resourceName);
            if (!fileNameFromResourceName.EndsWith(endingFileName))
            {
                continue;
            }

            using (var manifestResourceStream = assembly.GetManifestResourceStream(resourceName))
            {
                if (manifestResourceStream == null)
                {
                    continue;
                }

                using (var streamReader = new StreamReader(manifestResourceStream))
                {
                    return streamReader.ReadToEnd();
                }
            }
        }

        return null;
    }
    
    // https://stackoverflow.com/a/32176198/3764804
    private static string _GetFileNameFromResourceName(string resourceName)
    {
        var stringBuilder = new StringBuilder();
        var escapeDot = false;
        var haveExtension = false;

        for (var resourceNameIndex = resourceName.Length - 1;
            resourceNameIndex >= 0;
            resourceNameIndex--)
        {
            if (resourceName[resourceNameIndex] == '_')
            {
                escapeDot = true;
                continue;
            }

            if (resourceName[resourceNameIndex] == '.')
            {
                if (!escapeDot)
                {
                    if (haveExtension)
                    {
                        stringBuilder.Append('\\');
                        continue;
                    }

                    haveExtension = true;
                }
            }
            else
            {
                escapeDot = false;
            }

            stringBuilder.Append(resourceName[resourceNameIndex]);
        }

        var fileName = Path.GetDirectoryName(stringBuilder.ToString());
        return fileName == null ? null : new string(fileName.Reverse().ToArray());
    }
}

Upvotes: 4

Matteo Gariglio
Matteo Gariglio

Reputation: 522

As indicated by SonarCloud better to do:

public class Example
{
    public static void Main()
    { 
        // Compliant: type of the current class
        Assembly assembly = typeof(Example).Assembly; 
        Console.WriteLine("Assembly name: {0}", assem.FullName);

        // Non-compliant
        Assembly assembly = Assembly.GetExecutingAssembly();
        Console.WriteLine("Assembly name: {0}", assem.FullName);
    }
}

Upvotes: 3

Saeb Amini
Saeb Amini

Reputation: 24400

I wanted to read the embedded resource just as a byte array (without assuming any specific encoding), and I ended up using a MemoryStream which makes it very simple:

using var resStream = assembly.GetManifestResourceStream(GetType(), "file.txt");
var ms = new MemoryStream();
await resStream .CopyToAsync(ms);
var bytes = ms.ToArray();

Upvotes: 2

schlebe
schlebe

Reputation: 3716

For users that are using VB.Net

Imports System.IO
Imports System.Reflection

Dim reader As StreamReader
Dim ass As Assembly = Assembly.GetExecutingAssembly()
Dim sFileName = "MyApplicationName.JavaScript.js" 
Dim reader = New StreamReader(ass.GetManifestResourceStream(sFileName))
Dim sScriptText = reader.ReadToEnd()
reader.Close()

where MyApplicationName is namespace of my application. It is not the assembly name. This name is define in project's properties (Application tab).

If you don't find correct resource name, you can use GetManifestResourceNames() function

Dim resourceName() As String = ass.GetManifestResourceNames()

or

Dim sName As String 
    = ass.GetManifestResourceNames()
        .Single(Function(x) x.EndsWith("JavaScript.js"))

or

Dim sNameList 
    = ass.GetManifestResourceNames()
        .Where(Function(x As String) x.EndsWith(".js"))

Upvotes: -1

Nightfall
Nightfall

Reputation: 127

For all the people that just quickly want the text of a hardcoded file in winforms;

  1. Right-click your application in the solution explorer > Resources > Add your file.
  2. Click on it, and in the properties tab set the "FileType" to "Text".
  3. In your program just do Resources.<name of resource>.toString(); to read the file.

I would not recommend this as best practice or anything, but it works quickly and does what it needs to do.

Upvotes: 0

Dietrich Baumgarten
Dietrich Baumgarten

Reputation: 704

Some VS .NET project types don’t auto-generate a .NET (.resx) file. The following steps add a Resource file to your project:

  1. Right-click the project node and select Add/New Item, scroll to Resources File. In the Name box choose an appropriate name, for instance Resources and click the button Add.
  2. The resource file Resources.resx is added to the project and can be seen as a node in the solution explorer.
  3. Actually, two files are created, there is also an auto-generated C# class Resources.Designer.cs. Don’t edit it, it is maintained by VS. The file contains a class named Resources.

Now you can add a text file as a resource, for example an xml file:

  1. Double-click Resources.resx. Select Add Resource > Add Existing File and scroll to the file you want to be included. Leave the default value Internal for Access Modify.
  2. An icon represents the new resource item. If selected, the property pane shows its properties. For xml files, under the property Encoding select Unicode (UTF-8) – Codepage 65001 instead of the default local codepage. For other text files select the correct encoding of this file, for example codepage 1252.
  3. For text files like xml files, the class Resources has a property of type string that is named after the included file. If the file name is e.g. RibbonManifest.xml, then the property should have the name RibbonManifest. You find the exact name in the code file Resources.Designer.cs.
  4. Use the string property like any other string property, for example: string xml = Resources.RibbonManifest. The general form is ResourceFileName.IncludedTextFileName. Don’t use ResourceManager.GetString since the get-function of the string property has done that already.

Upvotes: 5

Chris Laplante
Chris Laplante

Reputation: 29658

Basically, you use System.Reflection to get a reference to the current Assembly. Then, you use GetManifestResourceStream().

Example, from the page I posted:

Note: need to add using System.Reflection; for this to work

   Assembly _assembly;
   StreamReader _textStreamReader;

   try
   {
      _assembly = Assembly.GetExecutingAssembly();
      _textStreamReader = new StreamReader(_assembly.GetManifestResourceStream("MyNamespace.MyTextFile.txt"));
   }
   catch
   {
      MessageBox.Show("Error accessing resources!");
   }

Upvotes: 98

miciry89
miciry89

Reputation: 306

adding e.g. Testfile.sql Project Menu -> Properties -> Resources -> Add Existing file

    string queryFromResourceFile = Properties.Resources.Testfile.ToString();

enter image description here

Upvotes: 19

Contango
Contango

Reputation: 80272

You can add a file as a resource using two separate methods.

The C# code required to access the file is different, depending on the method used to add the file in the first place.

Method 1: Add existing file, set property to Embedded Resource

Add the file to your project, then set the type to Embedded Resource.

NOTE: If you add the file using this method, you can use GetManifestResourceStream to access it (see answer from @dtb).

enter image description here

Method 2: Add file to Resources.resx

Open up the Resources.resx file, use the dropdown box to add the file, set Access Modifier to public.

NOTE: If you add the file using this method, you can use Properties.Resources to access it (see answer from @Night Walker).

enter image description here

Upvotes: 197

Jamisco
Jamisco

Reputation: 1862

The answer is quite simple, simply do this if you added the file directly from the resources.resx.

string textInResourceFile = fileNameSpace.Properties.Resources.fileName;

With that line of code, the text from the file is directly read from the file and put into the string variable.

Upvotes: 3

Awesomni.Codes
Awesomni.Codes

Reputation: 2430

I was annoyed that you had to always include the namespace and the folder in the string. I wanted to simplify the access to the embedded resources. This is why I wrote this little class. Feel free to use and improve!

Usage:

using(Stream stream = EmbeddedResources.ExecutingResources.GetStream("filename.txt"))
{
 //...
}

Class:

public class EmbeddedResources
{
    private static readonly Lazy<EmbeddedResources> _callingResources = new Lazy<EmbeddedResources>(() => new EmbeddedResources(Assembly.GetCallingAssembly()));

    private static readonly Lazy<EmbeddedResources> _entryResources = new Lazy<EmbeddedResources>(() => new EmbeddedResources(Assembly.GetEntryAssembly()));

    private static readonly Lazy<EmbeddedResources> _executingResources = new Lazy<EmbeddedResources>(() => new EmbeddedResources(Assembly.GetExecutingAssembly()));

    private readonly Assembly _assembly;

    private readonly string[] _resources;

    public EmbeddedResources(Assembly assembly)
    {
        _assembly = assembly;
        _resources = assembly.GetManifestResourceNames();
    }

    public static EmbeddedResources CallingResources => _callingResources.Value;

    public static EmbeddedResources EntryResources => _entryResources.Value;

    public static EmbeddedResources ExecutingResources => _executingResources.Value;

    public Stream GetStream(string resName) => _assembly.GetManifestResourceStream(_resources.Single(s => s.Contains(resName)));

}

Upvotes: 1

Bimo
Bimo

Reputation: 6597

After reading all the solutions posted here. This is how I solved it:

// How to embedded a "Text file" inside of a C# project
//   and read it as a resource from c# code:
//
// (1) Add Text File to Project.  example: 'myfile.txt'
//
// (2) Change Text File Properties:
//      Build-action: EmbeddedResource
//      Logical-name: myfile.txt      
//          (note only 1 dot permitted in filename)
//
// (3) from c# get the string for the entire embedded file as follows:
//
//     string myfile = GetEmbeddedResourceFile("myfile.txt");

public static string GetEmbeddedResourceFile(string filename) {
    var a = System.Reflection.Assembly.GetExecutingAssembly();
    using (var s = a.GetManifestResourceStream(filename))
    using (var r = new System.IO.StreamReader(s))
    {
        string result = r.ReadToEnd();
        return result;
    }
    return "";      
}

Upvotes: 4

t3chb0t
t3chb0t

Reputation: 18665

By all your powers combined I use this helper class for reading resources from any assembly and any namespace in a generic way.

public class ResourceReader
{
    public static IEnumerable<string> FindEmbededResources<TAssembly>(Func<string, bool> predicate)
    {
        if (predicate == null) throw new ArgumentNullException(nameof(predicate));

        return
            GetEmbededResourceNames<TAssembly>()
                .Where(predicate)
                .Select(name => ReadEmbededResource(typeof(TAssembly), name))
                .Where(x => !string.IsNullOrEmpty(x));
    }

    public static IEnumerable<string> GetEmbededResourceNames<TAssembly>()
    {
        var assembly = Assembly.GetAssembly(typeof(TAssembly));
        return assembly.GetManifestResourceNames();
    }

    public static string ReadEmbededResource<TAssembly, TNamespace>(string name)
    {
        if (string.IsNullOrEmpty(name)) throw new ArgumentNullException(nameof(name));
        return ReadEmbededResource(typeof(TAssembly), typeof(TNamespace), name);
    }

    public static string ReadEmbededResource(Type assemblyType, Type namespaceType, string name)
    {
        if (assemblyType == null) throw new ArgumentNullException(nameof(assemblyType));
        if (namespaceType == null) throw new ArgumentNullException(nameof(namespaceType));
        if (string.IsNullOrEmpty(name)) throw new ArgumentNullException(nameof(name));

        return ReadEmbededResource(assemblyType, $"{namespaceType.Namespace}.{name}");
    }

    public static string ReadEmbededResource(Type assemblyType, string name)
    {
        if (assemblyType == null) throw new ArgumentNullException(nameof(assemblyType));
        if (string.IsNullOrEmpty(name)) throw new ArgumentNullException(nameof(name));

        var assembly = Assembly.GetAssembly(assemblyType);
        using (var resourceStream = assembly.GetManifestResourceStream(name))
        {
            if (resourceStream == null) return null;
            using (var streamReader = new StreamReader(resourceStream))
            {
                return streamReader.ReadToEnd();
            }
        }
    }
}

Upvotes: 9

Sith2021
Sith2021

Reputation: 3716

I read an embedded resource text file use:

    /// <summary>
    /// Converts to generic list a byte array
    /// </summary>
    /// <param name="content">byte array (embedded resource)</param>
    /// <returns>generic list of strings</returns>
    private List<string> GetLines(byte[] content)
    {
        string s = Encoding.Default.GetString(content, 0, content.Length - 1);
        return new List<string>(s.Split(new[] { Environment.NewLine }, StringSplitOptions.None));
    }

Sample:

var template = GetLines(Properties.Resources.LasTemplate /* resource name */);

template.ForEach(ln =>
{
    Debug.WriteLine(ln);
});

Upvotes: 4

Night Walker
Night Walker

Reputation: 21260

When you added the file to the resources, you should select its Access Modifiers as public than you can make something like following.

byte[] clistAsByteArray = Properties.Resources.CLIST01;

CLIST01 is the name of the embedded file.

Actually you can go to the resources.Designer.cs and see what is the name of the getter.

Upvotes: 42

MasterCassidy
MasterCassidy

Reputation: 49

Read Embedded TXT FILE on Form Load Event.

Set the Variables Dynamically.

string f1 = "AppName.File1.Ext";
string f2 = "AppName.File2.Ext";
string f3 = "AppName.File3.Ext";

Call a Try Catch.

try 
{
     IncludeText(f1,f2,f3); 
     /// Pass the Resources Dynamically 
     /// through the call stack.
}

catch (Exception Ex)
{
     MessageBox.Show(Ex.Message);  
     /// Error for if the Stream is Null.
}

Create Void for IncludeText(), Visual Studio Does this for you. Click the Lightbulb to AutoGenerate The CodeBlock.

Put the following inside the Generated Code Block

Resource 1

var assembly = Assembly.GetExecutingAssembly();
using (Stream stream = assembly.GetManifestResourceStream(file1))
using (StreamReader reader = new StreamReader(stream))
{
string result1 = reader.ReadToEnd();
richTextBox1.AppendText(result1 + Environment.NewLine + Environment.NewLine );
}

Resource 2

var assembly = Assembly.GetExecutingAssembly();
using (Stream stream = assembly.GetManifestResourceStream(file2))
using (StreamReader reader = new StreamReader(stream))
{
string result2 = reader.ReadToEnd();
richTextBox1.AppendText(
result2 + Environment.NewLine + 
Environment.NewLine );
}

Resource 3

var assembly = Assembly.GetExecutingAssembly();
using (Stream stream = assembly.GetManifestResourceStream(file3))

using (StreamReader reader = new StreamReader(stream))
{
    string result3 = reader.ReadToEnd();
    richTextBox1.AppendText(result3);
}

If you wish to send the returned variable somewhere else, just call another function and...

using (StreamReader reader = new StreamReader(stream))
{
    string result3 = reader.ReadToEnd();
    ///richTextBox1.AppendText(result3);
    string extVar = result3;

    /// another try catch here.

   try {

   SendVariableToLocation(extVar)
   {
         //// Put Code Here.
   }

       }

  catch (Exception ex)
  {
    Messagebox.Show(ex.Message);
  }

}

What this achieved was this, a method to combine multiple txt files, and read their embedded data, inside a single rich text box. which was my desired effect with this sample of Code.

Upvotes: -1

dreamwork801
dreamwork801

Reputation: 133

I know this is old, but I just wanted to point out for NETMF (.Net MicroFramework), you can easily do this:

string response = Resources.GetString(Resources.StringResources.MyFileName);

Since NETMF doesn't have GetManifestResourceStream

Upvotes: 6

Peter Gfader
Peter Gfader

Reputation: 7741

Something I learned just now is that your file is not allowed to have a "." (dot) in the filename.

A "." in filename is no good.

Templates.plainEmailBodyTemplate-en.txt --> Works!!!
Templates.plainEmailBodyTemplate.en.txt --> doesn't work via GetManifestResourceStream()

Probably because the framework gets confused over namespaces vs filename...

Upvotes: 11

S_Teo
S_Teo

Reputation: 131

I know it is an old thread, but this is what worked for me :

  1. add the text file to the project resources
  2. set the access modifier to public, as showed above by Andrew Hill

  3. read the text like this :

    textBox1 = new TextBox();
textBox1.Text = Properties.Resources.SomeText;

The text that I added to the resources: 'SomeText.txt'

Upvotes: 13

Andrew Hill
Andrew Hill

Reputation: 2030

In Visual Studio you can directly embed access to a file resource via the Resources tab of the Project properties ("Analytics" in this example). visual studio screen shot - Resources tab

The resulting file can then be accessed as a byte array by 

byte[] jsonSecrets = GoogleAnalyticsExtractor.Properties.Resources.client_secrets_reporter;

Should you need it as a stream, then ( from https://stackoverflow.com/a/4736185/432976 )

Stream stream = new MemoryStream(jsonSecrets)

Upvotes: 84

Timmerz
Timmerz

Reputation: 6199

You can also use this simplified version of @dtb's answer:

public string GetEmbeddedResource(string ns, string res)
{
    using (var reader = new StreamReader(Assembly.GetExecutingAssembly().GetManifestResourceStream(string.Format("{0}.{1}", ns, res))))
    {
        return reader.ReadToEnd();
    }
}

Upvotes: 10

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