CODEWITHSUNDEEP
pythonselenium
user3870509
user3870509

Reputation: 357

How to find an element by href value using selenium python?

I have href value of an anchor tag which only have href value as attribute. Now I want to find the element in the page which have same value as my href value and click it. I am unable to find any way of doing this using standard selenium methods.How can I do this? Basically these are the functions I found but it seems that I can't use any of these:

find_element_by_id
find_element_by_name
find_element_by_xpath
find_element_by_link_text
find_element_by_partial_link_text
find_element_by_tag_name
find_element_by_class_name
find_element_by_css_selector

Upvotes: 30

Views: 170094

Answers (6)

Adam Gonzales
Adam Gonzales

Reputation: 948

In versions 4 and later of Selenium, use find_element() combined with a CSS selector and the By class:

from selenium import webdriver
from selenium.webdriver.common.by import By

jobs_link = driver.find_element(By.CSS_SELECTOR, "[href='https://www.linkedin.com/jobs/?']")
jobs_link.click()

Upvotes: 0

Tom Kuschel
Tom Kuschel

Reputation: 765

When the button looks like

<a href="server_export.php" class="tab">&nbsp;Export</a>

and because possibly the text is translated, we cannot use the search for the text Export, so we have to search e.g. for server_export within the href and can e.g. click it with

driver.find_element(By.XPATH,'//a[contains(@href,"server_export")]').click()

Note: Using the recommended find_element(By.xxxxx, ...) format.

Upvotes: 3

Daniel
Daniel

Reputation: 191

I have a button called Your Profile with this html line

<a href="/registration/profile.html" rel="follow">Your Profile</a>

I have been trying everything so far find_element_by link, xpath, css selector with no luck. It returns error unable to find the element.

browser.find_element_by_partial_link_text("Your Profile")

browser.find_element_by_xpath('//a[contains(@href,"registration/profile.html")]')

Thanks

Upvotes: 1

Netra Shah
Netra Shah

Reputation: 151

You can try this:

driver.find_element_by_xpath('//a[contains(@href,"href")]')

Upvotes: 15

Dmytro Pastovenskyi
Dmytro Pastovenskyi

Reputation: 5419

You can use find_element_by_xpath functionality.

driver.find_element_by_xpath('//a[@href="'+url+'"]')

Upvotes: 59

rnevius
rnevius

Reputation: 27092

You would find the element by the CSS selector, as you would using vanilla CSS:

link = driver.find_element_by_css_selector('[href^=http://somelink.com/]')

You can also find the element by the link text:

link = driver.find_element_by_partial_link_text('somelink')

Upvotes: 8

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