Reputation:
I am trying to write a program that will find all acute triangle solutions after the user enters a min and max value (dmin and dmax). Right now I think I have the program working using only for() loops, but I need to change the first for() loop to a do{}while loop, which is confusing me. I'm not able to figure out how to write the do{}while loop so that is also includes these nested for() loops and the if statements. Everything I've tried either tells me b and c aren't being used or it just runs and provides no output. Here is my code with the for() loops.
double a = 0, b = 0, c = 0;
printf("Here are the acute triangle solutions the program found:\n");
for (c = dmin; c <= dmax, c++)
{
for (b = dmin; b <= dmax; b++)
{
for (a = dmin; a <= dmax; a++)
{
if (a * a + b * b - c == c * c ){ //
if (((a + b) > c) && ((b + c) > a) && ((b + a) > b))
{printf("(%lf %lf %lf)\n", a, b, c);}
//sum of two sides must be greater than the third
//and angle across from c must be <90 degrees
}
}
}
}
Upvotes: 1
Views: 608
Reputation: 2731
In a do while, you simply do an initialization before and the check after. It is really somewhat similar to what the system does for a for loop.
The following code:
for (c = dmin; c <= dmax, c++)
{
for (b = dmin; b <= dmax; b++)
{
for (a = dmin; a <= dmax; a++)
{
if (a * a + b * b - c == c * c ){ //
if (((a + b) > c) && ((b + c) > a) && ((c + a) > c))
{printf("(%lf %lf %lf)\n", a, b, c);}
//sum of two sides must be greater than the third
//and angle across from c must be <90 degrees
}
}
}
}
Becomes:
c = dmin;
if(c < dmax) { //Make sure not to run once if c is greater
do
{
for (b = dmin; b <= dmax; b++)
{
for (a = dmin; a <= dmax; a++)
{
if (a * a + b * b - c == c * c ){ //
if (((a + b) > c) && ((b + c) > a) && ((c + a) > b))
{printf("(%lf %lf %lf)\n", a, b, c);}
//sum of two sides must be greater than the third
//and angle across from c must be <90 degrees
}
}
}
} while( ++c <= dmax );
}
Upvotes: 1
Reputation: 36391
a for (e1;e2;e3) something
loop can be transformed in:
e1;
while (e2) {
something;
e3;
}
or:
e1;
if (e2) {
do {
something;
e3;
} while (e2);
}
Upvotes: 2