CODEWITHSUNDEEP
phpconditional-statements
Lee Valentine
Lee Valentine

Reputation: 95

PHP: If number is divisble by 3, minus 1 (2, 5, 8, 11 etc)

I have a loop that creates divs with some content from a database. I have a variable $current_count which I'm starting at value '0' which is the first iteration of my loop.

I am using:

if ($current_count == 0 || $current_count % 3 == 0) { echo '<div class="parent">'; }

To create a parent div at the very top of the loop, then again on every iteration divisible by 3. It looks like this (with numbers representing iteration):

0 <div class="parent">
0    <div class="child"></div>
1    <div class="child"></div>
2    <div class="child"></div>
3 <div class="parent">
3    <div class="child"></div>
4    <div class="child"></div>
5    <div class="child"></div>

But the problem is I can't work out how to close those divs, as they would close on different iterations. For example, the parent opened on iteration 0 would need to be closed at the end of iteration 2.

I need to basically say (pseudo-code): 

IF $current_count is equal to (division of 3, minus 1) { etc }

I have tried:

if ($current_count % 3 == (0 - 1)) {}
if ($current_count % (3 == 0) - 1) {}
if ($current_count % 3 == 0 - 1) {}

But none of these are returning true. Does anyone know a way I can do this?

Cheers, Lee.

UPDATE 1: Here's an example of the PHP code currently, to better explain what I'm trying to accomplish:

$current_count = '0';
$ret = '';

        foreach ( $brands as $index => $brand ) : 

if ($current_count == 0 || $current_count % 3 == 0) {
                    $ret.= '<div class="parent">'; //Start parent
                }

                $ret.= '<div class="child"></div>'; //Child

if ($current_count % 3 == (0 - 1)) { // IF LINE 2, 5, 8, 11 etc, NOT WORKING
                            $ret.= '</div>'; // End the parent
                        }

            $current_count++;
        endforeach;

Upvotes: 0

Views: 750

Answers (2)

antonius christian
antonius christian

Reputation: 1

if you do it like that it still divided by 3 and not solving the question.

it should be :

if( $key % 3 == 2 ){
   </div>
}

Upvotes: 0

Niranjan N Raju
Niranjan N Raju

Reputation: 11987

try this,

    for($i = 0; $i <= 10; $i++) {
         if($i % 3 == 0 && $i > 0)// $i > 0 condition because. 0 % 3 is equal to 0 only.
              echo $i - 1;// will echo 2,5,8
              echo "</div>";// in your case.
    }

Upvotes: 2

Related Questions