CODEWITHSUNDEEP
xmlxslt
Radoslaw Krasimirow
Radoslaw Krasimirow

Reputation: 1873

why <xsl:apply-templates/> outputs the values of all ancestors tags

As far as I know the XPath expression "/" should set the node context to the child axis of the root node. Here is the xml:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<test-case name="test-case-1">
    <object-under-test category="template" name="text-align"/>
    <parameters>
        <input name="text">text</input>
        <input name="min-lenght">8</input>
        <input name="align">left</input>
        <output name="result"/>
    </parameters>
    <criteria>
        <criterion class="equal" to="'text '"/>
    </criteria>
</test-case>

</xsl:stylesheet>

And this is the xsl:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
    <test>
        <xsl:apply-templates/>
    </test>
</xsl:template>
</xsl:stylesheet>

What is the default match pattern for <xsl:apply-templates>? Why I get as an output the values of all tags?

This is the output:

<?xml version="1.0" encoding="UTF-8"?>
<test>text 8 left</test>

Upvotes: 0

Views: 61

Answers (1)

michael.hor257k
michael.hor257k

Reputation: 117018

As far as I know the XPath expression "/" should set the node context to the child axis of the root node.

No, it sets the context to the / root node itself.

What is the default match pattern for <xsl:apply-templates>?

"In the absence of a select attribute, the xsl:apply-templates instruction processes all of the children of the current node." http://www.w3.org/TR/xslt/#section-Applying-Template-Rules

Why I get as an output the values of all tags?

It's because of the built-in template rules that are applied when your stylesheet does not have a template that matches the nodes you have applied templates to. In a nutshell, the built-in templates copy all descendant text nodes to the output.

Upvotes: 4

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