CODEWITHSUNDEEP
cprogram-entry-pointargvargc
Sean
Sean

Reputation: 1313

C - Storing main() arguments in an array

I am creating a multithreaded program utilizing bankers algorithm, have all of it hard coded and compiled, but I am having a problem filling the initial available array from user input

#DEFINE NUMBER_OF_RESOURCES 3

int available[NUMER_OF_RESOURCES];       //available will be length of argc i.i number of total resoruces

int main(int argc, char *argv[]) 
{

printf("AVAILABLE RESOURCE: \n [");
//Populate Available Resource Array
for (i = 1; i < argc; i++)
{
    available[i-1] = argv[i];
    printf("%d ", available[i]);
}
printf("] \n\n");
}

When executing with: ./a.out 10 7 5

It prints:

[1604031496 1604031499 1604031501 ]

Upvotes: 0

Views: 86

Answers (2)

R Sahu
R Sahu

Reputation: 206567

  1. Use atoi to convert a string to an int.
  2. Make sure you don't access available out of bounds.
for (i = 1; i < argc && i < NUMER_OF_RESOURCES+1; i++)
{
    available[i-1] = atoi(argv[i]);
    printf("%d ", available[i-1]);
}

Upvotes: 0

Barmar
Barmar

Reputation: 780798

You can't convert strings to integers with ordinary assignment (you should have gotten a compiler warning about assigning char* to int without a cast). Call atoi() to parse the integers.

available[i-1] = atoi(argv[i]);

Upvotes: 5

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