CODEWITHSUNDEEP
pythonregexstring
jason
jason

Reputation: 4439

remove substring until end of the line

I have a string a

a="to be removed blah blah \r\nrow 2 blah blah\r\nrow 3 more blah blah \r\nto be removed more blah blah \r\nrow 5 final blah blah"

I want to do essentially the following a=a.replace_all("to be removed...\r\n" ,"")

so that the output looks like this:

"row 2 blah blah\r\nrow 3 more blah blah\r\nrow5 final blah blah"

however, I only know how the lines starts, not the rest

Upvotes: 1

Views: 808

Answers (3)

hwnd
hwnd

Reputation: 70732

Another approach without using a regular expression:

>>> a = "\r\n".join([i for i in a.splitlines() if not 'to be removed' in i])

Upvotes: 1

Learner
Learner

Reputation: 5292

Another try may be combination of search and sub function of re module-

>>>  a = "to be removed blah blah \r\nrow 2 blah blah\r\nrow 3 more blah blah \r\nto be removed more blah blah \r\nrow 5 final blah blah"
>>>  r = re.sub(re.search(r'to be removed blah blah[\s]+', a,re.I).group(), '', a)
>>>  print r

Upvotes: 0

TigerhawkT3
TigerhawkT3

Reputation: 49318

Use re.sub and put a wildcard . with repetition * that does not greedily include ? the \r\n:

>>> import re
>>> a = "to be removed blah blah \r\nrow 2 blah blah\r\nrow 3 more blah blah \r\nto be removed more blah blah \r\nrow 5 final blah blah"
>>> a = re.sub(r'to be removed.*?\r\n', '', a)
>>> a
'row 2 blah blah\r\nrow 3 more blah blah \r\nrow 5 final blah blah'

Upvotes: 4

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