CODEWITHSUNDEEP
pythonpython-3.x
Martin
Martin

Reputation: 13

Read first number of user input

I need a bit of help. I don't understand what I am doing wrong. I need code that checks the first number of user input. For example I enter the numbers 34566 and it looks at the first number and prints 'he' or 'she'.

Maybe some one can give me some advice how to solve it.

print("Sisesta isikukood")
isikukood[0] = int(input())

if (isikukood[0] == 1 or isikukood[0]== 3 or isikukood[0]== 5):
    print("He")
else:
    if isikukood[0] == 2 or isikukood[0]== 4 or isikukood[0] == 6:
        print("She")
    else:
        print("Vale isikukood")

Upvotes: 1

Views: 3512

Answers (2)

Harry
Harry

Reputation: 181

Get the input as a string. Then get the first number of that input like this isikukood[:1]. As the first number is now a string (not integer) you should compare it with a string.

print("Sisesta isikukood")
isikukood = str(input())

if (isikukood[:1] == '1' or isikukood[:1] == '3' or isikukood[:1] == '5'):
    print("He")
elif isikukood[:1] == '2' or isikukood[:1]== '4' or isikukood[:1] == '6':
    print("She")
else:
    print("Vale isikukood")

Edu :)

Upvotes: 0

falsetru
falsetru

Reputation: 369124

Instead of convert the string (the value returned by input()), leave it as a string. And you can use index operator to get the first character:

print("Sisesta isikukood")
num = input()  # no `int(..)`

if num[:1] in ('1', '3', '5'):
    print("He")
elif num[:1] in ('2', '4', '6'):
    print("She")
else:
    print("Vale isikukood")

NOTE: The characters should be compared with characters. ('1', '3', '5', ... instead of 1, 3, 5)

Upvotes: 1

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