CODEWITHSUNDEEP
arraysstringswift
Chris Tope
Chris Tope

Reputation: 133

Swift: Check String if it has an element in an Array

I want to check if a string contains at least one element in an array.

I tried this but I think it's too long. Imagine if I want all the alphabet in the if statement. I hope there is a proper way to do this.

var str = "Hello, playground."

let typeString = NSString(string: str)

if typeString.containsString("a") || typeString.containsString("e") || typeString.containsString("i") || typeString.containsString("o") || typeString.containsString("u") {
print("yes")
} else { 
print("no")
}
// yes

I tried using an array but it doesn't work. It needs all of the elements in an array to have a result of "yes".

let vowels = ["a", "e", "i", "o", "u"]
if typeString.containsString("\(vowels)") {
print("yes")
} else {
print("no")
}
// no

Btw, I'm still a newbie and still learning. Hope someone can help. Thanks

Upvotes: 5

Views: 1239

Answers (2)

Leo Dabus
Leo Dabus

Reputation: 236360

You can create two sets with the string characters and check its intersection:

let str = "Hello, playground."
let set = Set("aeiou")
let intersection = Set(str).intersection(set)
if !intersection.isEmpty {
    print("Vogals found:", intersection)                        // {"u", "o", "e", "a"}
    print("Vogals not found:", set.subtracting(intersection))   // {"i"}
} else {
    print("No vogal found")
}

Upvotes: 7

mn1
mn1

Reputation: 509

Try using this switch statements. 

let mySentence = "Hello Motto"
var findMyVowel: Character = "a" 
switch findMyVowel { 
case "a","e","i","o","u": 
    print("yes") 
default:
    print("no")
} 
mySentence.containsString("e")

Upvotes: 0

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