Reputation: 311
I'm having trouble with a function returning the original array as opposed to the sorted array. I tried to slice the array and return the sorted but it is not working. Any ideas on how to fix this?
function sortArr( comparator, array ){
var newArray = array.slice();
for(var i = 0; i < newArray.size; i++)
{
var min = i;
for(var x = i; x < newArray.size; x++)
{
if(comparator(newArray[min],newArray[x]) == true)
{
min = x;
}
}
var temp = newArray[i];
newArray[i] = newArray[min];
newArray[min] = temp;
}
return newArray;
}
I fixed the function:
function sortArr( comparator, array ){
/*your code here*/
var i, x;
var min;
var newArray = array.slice();
for(i = 0; i < newArray.length - 1; i++)
{
min = i;
for(x = i + 1; x < newArray.length; x++)
{
if(comparator(newArray[min],newArray[x]) == true)
{
min = x;
}
}
if(min != i){
var temp = newArray[i];
newArray[i] = newArray[min];
newArray[min] = temp;
}
}
return newArray;
}
Upvotes: 1
Views: 2900
Reputation: 1
{"index.js":"var globalArray = [5, 6, 3, 2, 9];
function nonMutatingSort(arr) {
let newArr = globalArray.slice();\n let emptyArr = [];
return emptyArr.concat(newArr).sort();
}
nonMutatingSort(globalArray);"}
Upvotes: -2
Reputation: 21766
Your sorting algorithm doesn't look quite right. For a start the swapping of values should be inside the if
statement. I would also advise to look at @Oriol's solution which is far more elegant.
function sortArr( comparator, array ){
var newArray = array.slice();
for(var i = 0; i < newArray.size; i++)
{
var min = i;
for(var x = i; x < newArray.size; x++)
{
if(comparator(newArray[min],newArray[x]) == true)
{
var temp = newArray[i];
newArray[i] = newArray[min];
newArray[min] = temp;
min = x;
}
}
}
return newArray;
}
Upvotes: 0
Reputation: 287960
Copy the array with slice
and then use native sort
:
function sortArr(comparator, array) {
return array.slice().sort(function(a,b) {
return comparator(a,b) * 2 - 1;
});
}
Upvotes: 7