CODEWITHSUNDEEP
androidparse-platform
user3803709
user3803709

Reputation: 107

Android Parse Query Retrieving Columns

So this is a very basic question but I've really hit a roadblock here. I've attempted quite a few things but I can't really understand how to extract the data from my parse table and get it into my app. I went through all the tutorials and still can't connect the dots.

What I'm trying to do is the following:

enter image description here

I want my app to be able to display every persons name who has a "human" designation. I've tried the following base code: 

ParseQuery<ParseObject> query = ParseQuery.getQuery("PersonClass");
    query.whereEqualTo("PersonType","human");
    query.findInBackground(new FindCallback<ParseObject>() {
        public void done(List<ParseObject> personList, ParseException e) {
            if (e == null) {                  
               ***HERE IS WHERE I"M CONFUSED ABOUT HOW TO EXTRACT THE DATA!!!!**
            } else {

            }
        }
    });

So the results I WOULD LIKE to see would be a return of "Steve" and "Gary" as they are both human designations

Where do I input data to point it towards searching through the specific column of "PersonsName" and then once it is pointed in that direction, how would I extract that data from this?

Upvotes: 0

Views: 441

Answers (2)

Ved
Ved

Reputation: 1077

Try this : 

ParseQuery<ParseObject> query = ParseQuery.getQuery("PersonClass");
query.whereEqualTo("PersonType","human");
query.findInBackground(new FindCallback<ParseObject>() {

  @Override
  public void done(List<ParseObject> personList, ParseException e) {
    if (e == null) {    
        if(personList.size()>0 ){             
            for (ParseObject person : personList) {
                String pearsonName=person.getString("PersonsName");
             }
        }else{
             // No records found
        }
    } else {
      //Handle the exception
    }
  }
});

Upvotes: 1

Kishore Jethava
Kishore Jethava

Reputation: 6834

do like this

get every Person object from list and get PearsonName from that Pearson object

ParseQuery<ParseObject> query = ParseQuery.getQuery("PersonClass");
query.whereEqualTo("PersonType","human");
query.findInBackground(new FindCallback<ParseObject>() {
    public void done(List<ParseObject> personList, ParseException e) {
        if (e == null && personList.size() > 0) {                  
            for (ParseObject person : personList) {
                String pearsonName=personList.getString("PearsonName");
            }
        } else {

        }
    }
});

Upvotes: 1

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