CODEWITHSUNDEEP
pythonwhoosh
daniel_zeng
daniel_zeng

Reputation: 53

whoosh exact match for a phrase

I want to find a phrase in a document, I've used the codes in the quick start.

>>> from whoosh.index import create_in
>>> from whoosh.fields import *
>>> schema = Schema(title=TEXT(stored=True), path=ID(stored=True), content=TEXT)
>>> ix = create_in("indexdir", schema)
>>> writer = ix.writer()
>>> writer.add_document(title=u"First document", path=u"/a", content=u"This is the first document we've added!")
>>> writer.add_document(title=u"Second document", path=u"/b",  content=u"The second one is even more interesting!")
>>> writer.commit()
>>> from whoosh.qparser import QueryParser
>>> with ix.searcher() as searcher:
        query = QueryParser("content", ix.schema).parse("first")
        results = searcher.search(query)
        results[0]

    result: {"title": u"First document", "path": u"/a"}

But then I find they will split the keywords into several single word and then search the document. If I want to search a phrase like "the first guy here in the document", what should I do.

On the document ,it said, use

"it is a phrase"

if I want to search for:

it is a phrase.

That confuses me.

Besides, here is a class ,which seems can help me , but I don't know how to use it.

class whoosh.query.Phrase(fieldname, words, slop=1, boost=1.0, char_ranges=None)
 Matches documents containing a given phrase.

Update: I use it in this way, but there is no matches.

from whoosh.index import create_in
from whoosh.fields import *
schema = Schema(title=TEXT(stored=True), path=ID(stored=True),   content=TEXT)
ix = create_in("indexdir", schema)
writer = ix.writer()
writer.add_document(title=u"First document", path=u"/a",
                 content=u"This is the first document we've added!")
writer.add_document(title=u"Second document", path=u"/b",
               content=u"The second one is even more interesting!")
writer.commit()
from whoosh.query import Phrase

a = Phrase("content", u"the first")

results = ix.searcher().search(a)
print results

result:

Top 0 Results for Phrase('content', u'the first', slop=1, boost=1.000000) runtime=0.0>

Update according to theOther

with ix.searcher() as searcher:
    query = QueryParser("content", ix.schema).parse(**'"first x document"'**)
results = searcher.search(query)
print results[0]

result : Hit {'content': u"This is the first document we've added!", 'path': u'/a', 'title': u'First document'}>

I think there should be no matched result ,as there is no "first x document" in the document. Otherwise, it is not an exact match.

Upvotes: 5

Views: 4302

Answers (2)

Max
Max

Reputation: 1805

To find a phrase in a content, use phrase=True when defining Schema as follows

schema = Schema(title=TEXT(stored=True), content=TEXT(phrase=True))

Then simply use double quotes within single ones as follows

query = QueryParser("content", schema=ix.schema).parse('"exact phrase"')

Upvotes: 1

Assem
Assem

Reputation: 12097

You should give Phrase a list of words not a string as second argument, and also eliminate the because it is a stop word:

a = Phrase("content", [u"first",u"document"])

instead of

a = Phrase("content", u"the first")

Read in documentation:

class whoosh.query.Phrase(fieldname, words, slop=1, boost=1.0, char_ranges=None)
Matches documents containing a given phrase.

Parameters:

fieldname – the field to search.

words – a list of words (unicode strings) in the phrase.

The natural use of phrase search in whoosh is by using Quotes " " in QueryParser:

>>> with ix.searcher() as searcher:
        query = QueryParser("content", ix.schema).parse('"first document"')
        results = searcher.search(query)
        results[0]

Update: for "first x document" what it matches, it is because x and all one-character words are stop-words and are filtered.

Upvotes: 5

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